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kifflom [539]
3 years ago
15

For every disubstituted cyclohexane, we can draw a Haworth projection and two chair conformations. This is true for all disubsti

tuted cyclohexanes, including cis-1,3-dimethylcyclohexane and trans-1,3-dimethylcyclohexane.
True or False?

Chemistry
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

True.

Explanation:

Both Haworth and chair conformations can be used to represent disubstituted cyclohexanes. However, <u>the energies for each chair conformation are different</u>, thus one conformation will be more favored than the other.

For the 1,3-cyclohexanes, the most stable conformation of the <em>cis</em> isomer has both methyl groups in equatorial positions. Any conformation of the <em>trans</em> isomer puts a methyl group in an axial position. Therefore, the <em>trans</em> isomer has more energy than the <em>cis</em> isomer. We need to remember, though, that <em>cis </em>and <em>trans</em> isomers can’t be interconverted and there is no equilibrium between these.

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Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

where,  

R = -8.315 J / mo

T = 298 K

For reaction,

1. K′eq1=270,

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 270

=  - 8.315 x 298 x 5.59

= - 13,851.293 J / mo

= - 13.85 kj/mol

2. K′eq2=890

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 890

=  - 8.315 x 298 x 6.79

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therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

6 0
3 years ago
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3 years ago
Can someone explain the steps for balancing chemical equations in depth?
m_a_m_a [10]

Answer:

Steps explained below

Explanation:

To explain balancing of chemical equations, I will make use of an example equation where Hydrogen and oxygen react to form water.

H2 + O2 = H2O

Now, the equation I've listed above is an unbalanced chemical equation. It can be balanced by the following steps;

Step 1: Identify the elements on both the left Hand side and the right hand side.

In this case;

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On the right hand side, we have H and I also.

Step 2: Identify the number of atoms of each element on both the left and right hand sides.

On the left, H has 2 atoms and O has 2 atoms.

On the right, H has 2 atoms and O has 1 atom.

Step 3: For the equation to be balanced, the number of atoms of each element on the right and left hand side must be the same.

Thus,

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So, we now have;

H2 + O2 = 2H2O

Step 4: Check equation: We now have;

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Our left hand side remains 2 atoms of H and 2 atoms of O. But on the right, we now have;

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Which means atoms of H is not balanced with the left side.

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3 0
2 years ago
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Explanation-

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2 years ago
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