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kifflom [539]
3 years ago
15

For every disubstituted cyclohexane, we can draw a Haworth projection and two chair conformations. This is true for all disubsti

tuted cyclohexanes, including cis-1,3-dimethylcyclohexane and trans-1,3-dimethylcyclohexane.
True or False?

Chemistry
1 answer:
Troyanec [42]3 years ago
3 0

Answer:

True.

Explanation:

Both Haworth and chair conformations can be used to represent disubstituted cyclohexanes. However, <u>the energies for each chair conformation are different</u>, thus one conformation will be more favored than the other.

For the 1,3-cyclohexanes, the most stable conformation of the <em>cis</em> isomer has both methyl groups in equatorial positions. Any conformation of the <em>trans</em> isomer puts a methyl group in an axial position. Therefore, the <em>trans</em> isomer has more energy than the <em>cis</em> isomer. We need to remember, though, that <em>cis </em>and <em>trans</em> isomers can’t be interconverted and there is no equilibrium between these.

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D

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Answer:

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Explanation:

Chemical equation:

C₂H₆ +  O₂     →      CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C = 1

H = 12                                    H = 2

O = 2                                     O = 3

Step 2:

2C₂H₆ +  O₂     →      4CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

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