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MArishka [77]
4 years ago
8

The least electronegative element from among the following is

Chemistry
2 answers:
Anettt [7]4 years ago
8 0
The most appropriate answer is C !! Cs is most electropositive and thus least electronegative !!
sergiy2304 [10]4 years ago
3 0

Ci caesium atomic number 55 i took the test

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Explain with examples following characteristics of chemical reactions: a. Change of colour b. Evolution of gas c. Change of smel
Andrei [34K]

Answer:

Explanation:

a. change of colour:

A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products. The products have different molecular structures than the reactants. Different atoms and molecules radiate different colours of light. Hence, there usually is a change in colour during a chemical reaction.

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b. Evolution of gas:

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c. Change of smell :

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Eg: The chemical change that occurs when an egg is rotting produces the smell of sulfur.

d. Change of state:

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Eg: candle wax (solid) melts initially to produce molten wax (liquid)

plz mark as brainliest!!!!

4 0
4 years ago
What two types of matter are closest in<br> density? How do you know?<br> ings.
maks197457 [2]

Answer:

Density: The molecules of a liquid are packed relatively close together. Consequently, liquids are much denser than gases. The density of a liquid is typically about the same as the density of the solid state of the substance.

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I hope it helps you

7 0
3 years ago
Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
3 years ago
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