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sweet [91]
3 years ago
10

Always carry the microscope with________________-one on the ____________ and one underneath the____________ of the microscope

Chemistry
1 answer:
Ronch [10]3 years ago
5 0

Answer:

Always carry the microscope with two hands. One on the arm and one underneath the base of the microscope.

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The electrolyte that is used to make Hypochlorous Acid is made from Sodium Chloride (NaCl). the bottle says that the electrolyte
kumpel [21]

Answer:

63.9 grams. Yes, the Nacl was converted.  Maximum possible ppm is 540ppm.

Explanation:

I this is college level chemistry not regular high school chem.  

7 0
3 years ago
30.0 ml of an hf solution were titrated with 22.15 ml of a 0.122 m koh solution to reach the equivalence point. what is the mola
a_sh-v [17]
Answer is: molarity of hydrofluoric solution is 0.09 M.

Chemical reaction: HF(aq) + KOH(aq) → KF(aq) + H₂O(l).
V(HF) = 30.0 mL.
c(KOH) = 0.122 M.
V(KOH) = 22.15 mL:
c(HF) = ?.
From chemical reaction: n(HF) : n(KOH) = 1 : 1.
n(HF) = n(KOH).
c(HF) · V(HF) = c(KOH) · V(KOH).
c(HF) = c(KOH) · V(KOH) ÷ V(HF).
c(HF) = 0.122 M · 22.15 mL ÷ 30 mL:
c(HF) = 0.09 M.
8 0
3 years ago
Read 2 more answers
The pictures to the right, show two different models of the atom. Type in the letter of your answer. Which model best represents
Solnce55 [7]

Answer:

Model B

Explanation:

Just did it on Edgenuity.

6 0
3 years ago
Read 2 more answers
In a 28 g serving of cheese curls there are 247mg of sodium. How much sodium is in a 12.5 ounce bag
Marina86 [1]

Answer:

There should be about 3136.9mg of Na in a 12.5oz bag of cheese curls.when rounding if not rounded it would be 3126.04082143mg

Explanation:

12.5oz=354.4g

354.4/28=12.7

12.7*247=3136.9

6 0
3 years ago
The solubility of a compound with a molecular weight of 233.2 is determined to be 27.9 g in 125.0 g of water at 398 K. Express t
sp2606 [1]

Answer:

0.960 m

Explanation:

Given data

  • Mass of the solute: 27.9 g
  • Molar mass of the solute: 233.2 g/mol
  • Mass of the solvent: 125.0 g = 0.1250 kg

First, we will calculate the moles of solute.

27.9 g × (1 mol/233.2 g) = 0.120 mol

The molality of the compound is:

m = moles of solute / kilograms of solvent

m = 0.120 mol / 0.1250 kg

m = 0.960 m

5 0
2 years ago
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