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Cerrena [4.2K]
2 years ago
8

How far away is sirius from the sun in inches? ____ in miles? ____

Chemistry
1 answer:
earnstyle [38]2 years ago
6 0

Answer:

the answer is 26.718 inches or

26.76 miles

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Describe three skills people use to conduct scientific investigations
Kipish [7]
Observations, surveys, and models.
6 0
3 years ago
For the reaction 3h2(g) + n2(g) 2nh3(g), kc = 9.0 at 350°c. calculate g° at 350°c.
miss Akunina [59]
When ΔG° is the change in Gibbs free energy

So according to ΔG° formula:

ΔG° =  - R*T*(㏑K)

here when K = [NH3]^2/[N2][H2]^3 = Kc 

and Kc = 9 

and when T is the temperature in Kelvin = 350 + 273 = 623 K

and R is the universal gas constant = 8.314 1/mol.K

So by substitution in ΔG° formula:

∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)

           = - 4536 
4 0
3 years ago
Igneous rocks would most likely be found near:
geniusboy [140]

Answer:

the deep sea floor. Known as the oceanic crust.

Explanation:

The deep seafloor (the oceanic crust) is made almost entirely of basaltic rocks, with peridotite underneath in the mantle. Basalts are also erupted above the Earth's great subduction zones, either in volcanic island arcs or along the edges of continents.

Hope this helps :)

7 0
3 years ago
Cytokinesis happens differently for plant and animal cells. Both separate cytoplasm between two new daughter cells. However, whi
victus00 [196]

Answer:

animal cell

Explanation:

Cytokinesis -

It refers to the process of cell division, which takes place during mitosis, is known as cytokinesis.

The process of cytokinesis is different for animal cell and plant cell.

  • Where, in case of plant cell, a separation, known as cell plate is formed along the center of the parent cell, which is responsible for the separation of the cells.
  • Whereas, in case of animal cell, the plasma membrane contracts itself along the center, until the two daughter cells are separated from each other.

Hence, from the given information of the question,

The correct answer is animal cell.

7 0
3 years ago
You wish to prepare a buffer consisting of acetic acid and sodium acetate with a total acetic acetate plus acetate concentration
vovangra [49]

<u>Ans: Acetic acid = 90.3 mM and Sodium acetate = 160 mM</u>

Given:

Acetic Acid/Sodium Acetate buffer of pH = 5.0

Let HA = acetic acid

A- = sodium acetate

Total concentration [HA] + [A-] = 250 mM ------(1)

pKa(acetic acid) = 4.75

Based on Henderson-Hasselbalch equation

pH = pKa + log[A-]/[HA]

[A-]/[HA] = 10^(pH-pKa) = 10^(5-4.75) = 10^0.25 = 1.77

[A-] = 1.77[HA] -----(2)

From (1) and (2)

[HA] + 1.77[HA] = 250 mM

[HA] = 250/2.77 = 90.25 mM

[A-] = 1.77(90.25) = 159.74 mM



7 0
3 years ago
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