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tamaranim1 [39]
3 years ago
10

Determine if the numerical value describes a population parameter or a sample statistic. The average price of a car at the new c

ar dealership in town is $34,800.
Is it a Population Parameter or Sample Statistic
Mathematics
2 answers:
polet [3.4K]3 years ago
8 0

Answer: Population parameter

Step-by-step explanation:

We can describe this numerical value $34, 800 as a population parameter because it takes into consideration, the population of all the cars in the new car dealership in town.

While the population parameter considers the entire population, example, the total number of cars in the house, the sample statistics would only consider a sample of a very vast population.

This figure is a population parameter, because the population of cars in the car dealership can be measured. They are sizeable. Therefore, we can easily obtain the average price of the cars.

Travka [436]3 years ago
7 0

Answer:

Population parameter

Step-by-step explanation:

Since the average price of a whole town at a new dealership is described. A random sample from a town was not isolated for study. In fact the entire statistics of the town was considered in the mean price of a car. Hence, the average price given in our case will be a population parameter.

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Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.
eimsori [14]

Answer:

(a) 5^{8}

(b) 3

(c) 27

(d) \dfrac{1}{6}  

Step-by-step explanation:

We need simplify the given expressions.

(a)

Consider the given expression is

(5^4)(25^2)

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Using the properties of exponents we get

(5^4)(5^4)           [\because (a^m)^n=a^{mn}]

5^{4+4}                  [\because a^ma^n=a^{m+n}]

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(b)

Consider the given expression is

(9^{\frac{1}{3}})(3^{\frac{1}{3}})

((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})

Using the properties of exponents we get

(3^{\frac{2}{3}})(3^{\frac{1}{3}})           [\because (a^m)^n=a^{mn}]

3^{\frac{2}{3}+\frac{1}{3}}                 [\because a^ma^n=a^{m+n}]

3^{1}

3

(c)

Consider the given expression is

(\dfrac{1}{3})^{-3}

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(d)

Consider the given expression is

(6^4)(6^{-5})

Using the properties of exponents we get

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6 0
3 years ago
9+10=21
hodyreva [135]

The reason why people sometimes assume that the calculation 9 + 10 = 21 is as explained below.

<h3>How to calculate in number bases?</h3>

We want to find out the reason why people say that; 9 + 10 = 21

Now, the way you have explained it is one way to look at it by utilizing number bases to play around with the figures to arrive at 21.

However, another way is to use algebra trick pattern which is;

9 can be expressed as 3 * 3

Also, 10 can be expressed as 5 * 2. Thus, we now have;

(3 * 3) + (5 * 2)

The applying properties of algebra to cross multiply gives;

(3 * 2) + (5 * 3)

= 6 + 15

= 21

Now, though your explanation arrived at 21 and mine also 21, but those are not correct mathematical methods as 9 + 10 must be equal to 19 and not 21.

Read more about Number bases at; brainly.com/question/8649831

#SPJ1

6 0
2 years ago
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daser333 [38]
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3 years ago
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No.

Step-by-step explanation:

Standard form is

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So 6y - 2x = 10 is not in standard form.

Correct  is -2x + 6y = 10.

4 0
3 years ago
Read 2 more answers
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