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Mamont248 [21]
3 years ago
8

How can an experiment support or fail to support a hypothesis?

Physics
2 answers:
liraira [26]3 years ago
8 0

<u>Explanation: </u>

The first step of formation of scientific theory or law is formation of a testable question. Then building up of a hypothesis surrounding the question. Thereafter designing an experiment to test the hypothesis.

If the result of the experiment is positive, it supports the hypotheses. On the other hand, a negative result fails to suppose the hypothesis. It is very important to carefully choose and perform the experiment because the formation of the scientific law and theory is dependent on the experiment.

Alisiya [41]3 years ago
6 0

a hypothesis is given to explain a phenomena which has not been explained earlier. it can proved  by an experiment if that experiment gets the other results regarding that particular phenomena in agreement with that being predicted by the hypothesis and if  result doesnt match the prediction then the hypothesis is again  totally discarded at times.
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CAN SOMEONE EXPLAIN HOW TO DO THIS?!?!
Rzqust [24]
Both cars are canceling out the energy of each other. The energy that is left over because one car has a bigger kinetic energy is the energy that is going to move BOTH the cars.

First Car : <em>0.5 * 2000kg * 3m/s^2 = 10.24 KJ</em>

Second Car :<em> 0.5 * 2000kg * 2m/s^2 = 4 KJ</em>

Leftover Energy : <em>10.24 KJ - 4 KJ = 6.24 KJ
</em>
Movement of BOTH cars :<em /><em>
6.24 = 4000kg * v^2
</em>v =  √(6.24 / 4000) =0.04 m/s = 4 cm/s

3 0
4 years ago
(a) A 70-kg person at rest has an oxygen consumption rate Qhum = 14.5 liter/h, 2% of which is supplied by diffusion through the
nevsk [136]

Answer:

(a) fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b) [tex]r=26.008\ cm

Explanation:

(a)

  • Oxygen consumption rate of humans, Q_h=14.5\ L.hr^{-1}

area of human skin, A_h=1.7\ m^2

  • diffusion rate through skin of humans, d=2\%\ of\ Q_h
  • ∴d=\frac{2}{100} \times 14.5

d=0.29\ L.hr^{-1}

<u>Flux of diffusion rate, </u>

fd=\frac{d}{A}

fd=\frac{0.29}{17000}

fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b)Surface area for a spherical animal:[tex]A=4.\pi.r^2

Diffusion flux rate for animal:

fd=\frac{14.5}{A}

1.7058\times 10^{-5}=\frac{14.5}{4.\pi.r^2}

r=26.008\ cm

4 0
4 years ago
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3 years ago
The hubbles telescopes orbit is 5.6 x10 ^5 meters above earths suface. the telescope has a mass os 1.1 x10^4 kilograms. earth ex
Andru [333]
(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg

Fam
7 0
3 years ago
Argon in the amount of 1.5 kg fills a 0.04-m3 piston cylinder device at 550 kPa. The piston is now moved by changing the weights
Arlecino [84]

Answer:

               275 kPa

Explanation:

             mass of the gas=m=1.5 kg

             initial volume if the gas=V₁=0.04 m³

             initial pressure of the gas= P₁=550 kPa

as the condition is given final volume is double the initial volume

             V₂=final volume

             V₂=2 V₁

As the temperature is constant

             T₁=T₂=T

\frac{P1V1}{T1}=\frac{P2 V2}{T2}

putting the values in the equation.

\frac{P1V1}{T1}=\frac{P2 *2V1}{T2}

P₂=\frac{P1}{2}

P₂=\frac{550}{2}

P₂=275 kPa

So the final pressure of the gas is 275 kPa.

           

3 0
4 years ago
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