Upside down if its further than 1 focal point you have seen this with a spoon and enlarged right side up if closer than 1 focal point
The forces are the same like the third law of Newton states.I think
Answer:
The velocity will be v = 165.83[m/s]
Explanation:
This is a problem where the definition of kinetic energy can be applied, which can be determined with the following equation.
![E_{k}=\frac{1}{2}*m*v^{2}\\ where:\\m = mass = 80000[kg]\\v = velocity [m/s]\\E_{k}= kinetic energy [J]=1100000000[J]\\Replacing:\\v=\sqrt{\frac{2*E_{k} }{m} } \\v=\sqrt{\frac{2*1100000000 }{80000} }\\v=165.83[m/s]](https://tex.z-dn.net/?f=E_%7Bk%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av%5E%7B2%7D%5C%5C%20%20%20where%3A%5C%5Cm%20%3D%20mass%20%3D%2080000%5Bkg%5D%5C%5Cv%20%3D%20velocity%20%5Bm%2Fs%5D%5C%5CE_%7Bk%7D%3D%20kinetic%20energy%20%5BJ%5D%3D1100000000%5BJ%5D%5C%5CReplacing%3A%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B2%2AE_%7Bk%7D%20%7D%7Bm%7D%20%7D%20%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B2%2A1100000000%20%7D%7B80000%7D%20%7D%5C%5Cv%3D165.83%5Bm%2Fs%5D)
solution:
When an uncharged conducting object brought near to a charged insulating object there is a force on the conducting object to move the electrons within it to opposite sides of the conductor. That means there is a separation of charges in the conducting object in the presence of the charged insulating object near to it but the charge on the conducting object is neutral.
Thus, the conducting object is uncharged.
There is a force of attraction between the uncharged conducting object and the insulating object when it brought near to the insulating object.
Thus, there is a force on the conducting object.
The conductor remains uncharged and a force is exerted on it.
