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Svetlanka [38]
1 year ago
9

7 2. Name the independent variable: 3. Name the dependent variable:​

Physics
1 answer:
charle [14.2K]1 year ago
5 0

Answer:

independent variable is found on the x axis while dependent variable is found on the y axis

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Answer:

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3 0
2 years ago
The human body is a system of systems that rely on each other to sustain a life. Explain how.
Misha Larkins [42]
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4 0
2 years ago
Inside a NASA test vehicle, a 3.50-kg ball is pulled along by a horizontal ideal spring fixed to a friction-free table. The forc
erastova [34]
F(of spring)=230x=ma=3.5(5)=17.5=230x; x=0.07m.
3 0
2 years ago
6. A 2-kg ball B is traveling around in a circle of radius r1 = 1 m with a speed (vB)1 = 2 m/s. If the attached cord is pulled d
kipiarov [429]

Answer:

Explanation:

Given that,

Mass of ball m = 2kg

Ball traveling a radius of r1= 1m.

Speed of ball is Vb = 2m/s

Attached cord pulled down at a speed of Vr = 0.5m/s

Final speed V = 4m/s

Let find the transverse component of the final speed using

V² = Vr²+ Vθ²

4² = 0.5² + Vθ²

Vθ² = 4²—0.5²

Vθ² = 15.75

Vθ =√15.75

Vθ = 3.97 m/s.

Using the conservation of angular momentum,

(HA)1 = (HA)2

Mb • Vb • r1 = Mb • Vθ • r2

Mb cancels out

Vb • r1 = Vθ • r2

2 × 1 = 3.97 × r2

r2 = 2/3.97

r2 = 0.504m

The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m

The required time,

Using equation of motion

V = ∆r/t

Then,

t = ∆r/Vr

t = (r1—r2) / Vr

t = (1—0.504) / 0.5

t = 0.496/0.5

t = 0.992 second

7 0
3 years ago
Unlike a roller coaster, the seats in a Ferris wheel swivel so that the rider is always seated upright. An 80-ft-diameter Ferris
telo118 [61]

Answer:

a

   F_A  =425.42 \ N

b

  F_A_H  = 358.58 \ N

Explanation:

From the question we are told that

    The diameter of the Ferris wheel is  d  =  80 \ ft =  \frac{80}{3.281} =  24.383

    The  period of the Ferris wheel is  T  =  24 \ s

     The  mass of the passenger is  m_g  =  40 \ kg

The  apparent weight of the passenger at the lowest point is mathematically represented as

           F_A_L  =  F_c  + W

Where  F_c is the centripetal force on the passenger,  which is mathematically represented as

         F_c  =m *  r *  w^2

Where w is the angular velocity which is mathematically represented as

         w =  \frac{2* \pi   }{T}

substituting values

         w =  \frac{2* 3.142 }{24}

         w =  0.2618 \ rad/s

and  r  is the radius which is evaluated as r =  \frac{d}{2}

   substituting values

         r =  \frac{24.383}{2}

         r = 12.19 \ ft

So

          F_c  = 40 * 12.19* (0.2618)^2

          F_c  =  33.42 \ N

W is the weight which is mathematically represented as

           W =  40 * 9.8

           W =  392 \ N

So

         F_A    =  33.42 + 392

         F_A  =425.42 \ N

The  apparent weight of the passenger at the highest point is mathematically represented as

          F_A_H  =  W- F_c

substituting values

         F_A_H  = 392 -  33.42

         F_A_H  = 358.58 \ N

4 0
3 years ago
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