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kodGreya [7K]
3 years ago
7

The value of 2 in 204.75 is how many times the value of 2 in 103.52​

Mathematics
2 answers:
KengaRu [80]3 years ago
8 0

Answer:

1000.

Step-by-step explanation:

The Value of the 2 in 204.75, is 200.

The Value of the 2 in 103.52 is 0.02.

So to make the 0.02 become 200, you have to move the decimal point 3 spaces to the right.

Therefore, the 2 in 204.75 is 1000 times greater than the value of the 2 in 103.52.

I hope this helps!

Sloan [31]3 years ago
4 0
It would be 10000 times
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Factorise fully<br>6x - 8​
Amanda [17]

Answer:

2(3x+ 4)

I hope it helps

Pls mark as brainliest

3 0
3 years ago
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Are those expressions equivalent? Explain why or why not.
vova2212 [387]
42+35 is 77
7(6+5) is 77 so yes
Brainliest pls
5 0
3 years ago
Average rate of change help!!
frez [133]

Given that the function is f(x)=x^{3}-6 x^{2}+4 x+7

We need to determine the average rate of change over the interval 0 \leq x \leq 5

<u>Value of f(x) when x = 0:</u>

Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

f(0)=0-0+0+7

f(0)=7

Thus, the value of f(0) is 7.

<u>Value of f(x) when x = 5:</u>

Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7

f(5)=125-150+20+7

f(5)=2

Thus, the value of f(5) is 2.

<u>Average rate of change:</u>

The average rate of change can be determined using the formula,

Rate \ of \ change=\frac{f(b)-f(a)}{b-a}

where a=0 and b=5

Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

Rate \ of \ change=\frac{2-7}{5-0}

Rate \ of \ change=\frac{-5}{5}

Rate \ of \ change=-1

Thus, the average rate of change over the interval 0 \leq x \leq 5 is -1.

3 0
2 years ago
Please help! Will give brainliest to correct answer
saveliy_v [14]

Answer:

Correct option is (C).

Step-by-step explanation:

Because in figure,

°.°point B is fixed at plane.

.°.Center is B.

& °.° Image is enlargement.

.°. scale factor will be greater than 1

Now,

scale factor = A'B'/AB

= 24/6

= 3

So correct option is (C).

#$# HOPE YOU UNDERSTAND #$#

#$¥ THANK YOU ¥$#

❤ ☺ ☺ ☺ ☺ ☺ ☺ ❤

5 0
3 years ago
HELP ASAP PLEASE
Verizon [17]

Answer:

  • 1.25 g

Step-by-step explanation:

<u>Given:</u>

  • Initial mass is m = 80 g.
  • Half life = 10 days
  • Total time = 60 days

<u>Number of half-life periods:</u>

  • r = 60/10 = 6

<u>Equation for remaining sample:</u>

  • s = m*(1/2)^r
  • s = 80*(1/2)^6 = 80/64 = 1.25 g
5 0
2 years ago
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