Question

For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.
(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e.g, ABC.)


1. lead fluoride ________ (answer here )
2. aluminum hydroxide _________ (answer here )
A. Mg(OH)2
B. BaF2
C. Ag3PO4
D. AgI



Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.

lead fluoride


aluminum hydroxide

Ksp =

Ksp =


Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.

Answer 1

For lead fluoride Ksp = s³

For Aluminum hydroxide Ksp = s⁴

Explanation:

The expression for the solubility product can be written as the product of the concentration of the ions present in the solution.

PbF₂ → Pb²⁺ + 2 F⁻

Then the Ksp can be written as,

Ksp = [ Pb²⁺] [F⁻]²

If the concentration can be considered as s, then the Ksp can be written as,

Ksp = s× s² = s³

For Aluminum hydroxide on dissociation it gives 4 ions as,

Al(OH)₃ → Al³⁺ + 3 OH⁻

Ksp = [Al³⁺] [OH⁻]³

      = s × s³ = s⁴

Thus,For lead fluoride Ksp = s³

For Aluminum hydroxide Ksp = s⁴