D = m / V
0.736 = 225.0 / V
V = 225.0 / 0.736
V = 305.7 cm³
Answer:
1.9 L
Explanation:
Step 1: Given data
- Initial pressure (P₁): 1.5 atm
- Initial volume (V₁): 3.0 L
- Initial temperature (T₁): 293 K
- Final pressure (P₂): 2.5 atm
- Final temperature (T₂): 303 K
Step 2: Calculate the final volume of the gas
If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L
Answer:
For large rivers the problem is not simply a matter of deduction of consumptive use from runoff: it is more complex and the complexity is related to the changes in .
Explanation:
Answer: <span>Molecular geometry around each carbon atom in a saturated hydrocarbon is
Tetrahedral.
Explanation: </span> In saturated hydrocarbons (-CH₂-) the central atom (
carbon) is bonded to either three or two hydrogen atoms and one or two carbon atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to
Valence Shell Electron Pair Repulsion (VSEPR)
Theory the central atom with four bonding pair electrons and zero lone pair electrons will attain a
tetrahedral geometry with
bond angles of 109°.
Answer:
Oxidation
Explanation:
Mg loses 2e- for it to gain it's stability hence the reaction above is oxidation
note: Oxidation is the loss of electrons while reduction is the gain of electrons