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timama [110]
3 years ago
15

Practicing Function Inverses, find values a,b,c,d,e 50 Points = 25 points Thank you.

Mathematics
1 answer:
o-na [289]3 years ago
8 0

Answer:

a = -3.8

b = -2.6

c = 1.7

d = 4.4

e = 1.0

Step-by-step explanation:

Inverse just means that the x- and y-values are reversed. Notice how I didn't need to do any math to fill in the blanks; all the points are already given!

Please mark as Brainliest! :)

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On a number line, what is the distance between -9 and -5?
Makovka662 [10]

Answer:

The distance on a number line between -9 and -5 would be 4. This is kinda easy.

Step-by-step explanation:

4 0
3 years ago
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
3 years ago
Find the surface area of the prism.
navik [9.2K]

Answer:

I cant see it ill go on your page when you post it with the picture.

6 0
3 years ago
Read 2 more answers
While performing a vertical line test on a graph, you notice that the graph intercepts the vertical line twice. Which of the fol
MakcuM [25]

Answer:

The correct option is;

Because the vertical line intercepted the graph more than once, the graph is of a relation, but it is not a function

Step-by-step explanation:

Given that a function maps a given value of the input variable, to the output variable, we have that a relation that has two values of the dependent variable, for a given dependent variable is not a function

Therefore, a graph in which at one given value of the input variable, x, there are two values of the output variable y is not a graph of a function

With the vertical line test, if a vertical line drawn at any suitable location on the graph, intercepts the graph at more than two points, then the relationship shown on the graph is not a function.

6 0
3 years ago
What is an expression that equals 24 that includes an exponent
statuscvo [17]
5∧2(exponent of 2) - 1 =24
7 0
3 years ago
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