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lord [1]
3 years ago
6

HELP BIG Picture there a image

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0
The answer is the second one.
x=10   y=-20
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Suppose that a tea company estimates that its monthly cost is C(c) = 500x² + 100x and its monthly revenue is R(2) = -0.6x3 + 700
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Answer:

p(x) = 0.6x³ - 200x² + 500x- 300

Step-by-step explanation:

Given the cost function and revenue function as:

C(x) = 500x² + 100x

R(x) = -0.6x³ + 700x² – 400x + 300

To get the profit function:

p(x) = C(x) - R(x)

p(x) = 500x² + 100x -(-0.6x³ + 700x² – 400x + 300)

open the parenthesis

p(x) = 500x² + 100x + 0.6x³ - 700x² + 400x - 300

p(x) = + 0.6x³+500x² - 700x² + 100x+ 400x- 300

p(x) = 0.6x³ - 200x² + 500x- 300

Hence the profit function is expressed as p(x) = 0.6x³ - 200x² + 500x- 300

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Step-by-step explanation:

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