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3 years ago

What does a chemical formula like Na2CO3 tells us?

Chemistry

1 answer:

USPshnik [31]3 years ago

8 0

It has: 2 atoms of sodium (Na) 1 atom of Carbon 3 atoms of Oxygen bound together with ionic and polar-covalent bonds

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Why will liquids evaporate even at room temperature?

mr Goodwill [35]

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3 years ago

A phase is a part of a system with what type of composition?

TiliK225 [7]

Answer:

uniform composition.

Explanation:

A phase is a part of a system with uniform composition.

In physics and chemistry , a phase in a physically distinctive form of matter , such as solid , liquid , gas or plasma.
A phase matter is characterised by having relatively uniform chemical and physical properities . Phases are different from states of matter.
The states of matter (e.g ., solid , liquid , gas ) are phases but matter can exist in different phases and yet be in the same type of matter. For example , liquid mixtures can exist in multiple phases such as oily and aqueous phase.
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3 years ago

State the total number of electrons occupying all the p- orbitals in one atom of chlorine .

V125BC [204]

Answer:A chlorine atom in its ground state has a total of seven electrons in orbitals related to the atoms third energy level.

Explanation:

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3 years ago

Synthesis Decompisition O Combustion O Single Displacement O Double Displacement

BabaBlast [244]

Answer:

Synthesis

Explanation:

Nothing else works

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3 years ago

What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride

Savatey [412]

Given:

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

To determine:

The mass of CaCO3 produced

Explanation:

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol = 75 g

Ans: Mass of CaCO3 produced = 75 g

7 0

3 years ago