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3 years ago

What does a chemical formula like Na2CO3 tells us?

Chemistry

1 answer:

USPshnik [31]3 years ago

8 0

It has: 2 atoms of sodium (Na) 1 atom of Carbon 3 atoms of Oxygen bound together with ionic and polar-covalent bonds

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1 . a chemical bond formed by the electrostatic attraction between ions covalent bond

liberstina [14]

Explanation:

When there occurs sharing of electrons between two chemically combining atoms then it forms a covalent bond. Generally, a covalent bond is formed between two non-metals.

An ionic bond is defined as the bond formed due to transfer of one or more number of electrons from one atom to another. An ionic bond is always formed between a metal and a non-metal.

Every atom of an element will have orbitals in which electrons are found. These orbitals are known as energy level.

A molecule is defined as the smallest particle present in a substance or atom.

A metallic bond is formed due to mobile valence electrons shared by positive nuclei in a metallic crystal.

Thus, we can conclude that given statements are correctly matched as follows.

1). a chemical bond formed by the electrostatic attraction between ions - ionic bond

2). a chemical bond formed by two electrons that are shared between two atoms - covalent bond

3). the orbitals of an atom where electrons are found - energy level

4). the smallest particle of a covalently bonded substance - molecule

5). a bond characteristic of metals in which mobile valence electrons are shared among positive nuclei in the metallic crystal - metallic bond

7 0

2 years ago

Use the given data at 500 K to calculate ΔG°for the reaction

Anton [14]

Answer : The value of $\Delta G^o$ for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

$2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)$

First we have to calculate the enthalpy of reaction $(\Delta H^o)$ .

$\Delta H^o=H_f_{product}-H_f_{reactant}$

$\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]$

where,

$\Delta H^o$ = enthalpy of reaction = ?

n = number of moles

$\Delta H_f^0$ = standard enthalpy of formation

Now put all the given values in this expression, we get:

$\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]$

$\Delta H^o=-1035.6kJ=-1035600J$

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction $(\Delta S^o)$ .

$\Delta S^o=S_f_{product}-S_f_{reactant}$

$\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]$

where,

$\Delta S^o$ = entropy of reaction = ?

n = number of moles

$\Delta S_f^0$ = standard entropy of formation

Now put all the given values in this expression, we get:

$\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]$

$\Delta S^o=-153J/K$

Now we have to calculate the Gibbs free energy of reaction $(\Delta G^o)$ .

As we know that,

$\Delta G^o=\Delta H^o-T\Delta S^o$

At room temperature, the temperature is 500 K.

$\Delta G^o=(-1035600J)-(500K\times -153J/K)$

$\Delta G^o=-959100J=-959.1kJ$

Therefore, the value of $\Delta G^o$ for the reaction is -959.1 kJ

3 0

2 years ago

I have no idea how to do this help plz!

Wittaler [7]

The answes are
C)
Then it is
)A
Im doing this for class too bruh

8 0

2 years ago

Read 2 more answers

Which statement describes compounds?

Natasha2012 [34]

Answer:

Explanation:

4 0

2 years ago

Hydrochloric acid is the primary component of gastric juice in the stomach (see Chemistry in Action: GERD-Too Much Acid or Not E

olga nikolaevna [1]

Answer:

Acid: HCl(aq), conjugate base: Cl⁻(aq)

Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)

The rewrite reaction is shown below.

Explanation:

The acid compound is the one that loses an H⁺, and the compound formed when it happens is its conjugate base. The base compound is the acceptor of H⁺, and its conjugate acid is the compound formed (Brosted-Lowry theory).

So, the acid-base pairs are:

Acid: HCl(aq), conjugate base: Cl⁻(aq)

Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)

The TUMS® is an antacid, so it intends to reduce the concentration of the strong acid HCl. So, the forward reaction is favored. It can be represented with the forward arrow larger than the reversible arrow, as shown in the image below.

8 0

3 years ago