Answer:

Explanation:
Hello there!
In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:

Which can be solved for the final volume, V2, as shown below:

Thus, by plugging in the given data, we obtain:

Regards!
Answer:
0.175mol
Explanation:
Molarity of a solution can be calculated thus:
Molarity (M) = number of moles (n) / volume (V)
According to the information provided in this question, volume of NH4OH = 0.125L, molarity = 1.4M
Using; Molarity = n/V
1.4 = n/0.125
n = 0.175mol
Answer:
Kc = 0.075
Explanation:
The dissociation (α) is the initial quantity that ionized divided by the total dissolved. So, let's calling x the ionized quantity, and M the initial one:
α = x/M
x = M*α
x = 0.354M
For the stoichiometry of the reaction (2:1:1), the concentration of H₂ and I₂ must be half of the acid. So the equilibrium table must be:
2HI(g) ⇄ H₂(g) + I₂(g)
M 0 0 <em> Initial</em>
-0.354M +0.177M +0.177M <em>Reacts</em>
0.646M 0.177M 0.177M <em>Equilibrium</em>
The equilibrium constant Kc is the multiplication of the products' concentrations (elevated by their coefficients) divided by the multiplication of the reactants' concentrations (elevated by their coefficients):
![Kc = \frac{[H2]*[I2]}{[HI]^2}](https://tex.z-dn.net/?f=Kc%20%3D%20%5Cfrac%7B%5BH2%5D%2A%5BI2%5D%7D%7B%5BHI%5D%5E2%7D)


Kc = 0.075
B is the answer or check it out