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Anastasy [175]
3 years ago
5

Which planetary body was opportunity designed to explore?

Chemistry
1 answer:
11111nata11111 [884]3 years ago
3 0
The rover was designed to explore A.Mars
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Identify and describe the different forms of precipitation shown in the images.
Nutka1998 [239]

Answer:

It was first just snow but now its snow ball eggs that's what it looks like hope it helps:)

Explanation:

4 0
2 years ago
When 2 crystalline solid barium hydroxide octahydrate and crystalline solid ammonium nitrate are mixed in a beaker at room tempe
podryga [215]
It is endothermic reaction ΔH>0 (sign is +).
Because it is spontaneous reaction ΔG<span><0 (Gibbs free energy)
</span>ΔG=ΔH-TΔS, so must be TΔS>ΔH and ΔS<span>>0 (sign +).</span>
5 0
3 years ago
Which of the following combinations will result in a reaction that is spontaneous at all temperatures?
Katen [24]

Answer:

\huge\boxed{Option \ 2}

Explanation:

A reaction is spontaneous at all temperatures by the following combinations:

=> A negative enthalpy change ( \triangle H < 0 )

=> A positive entropy change ( \triangle S > 0 )

See the attached file for more better understanding!

8 0
3 years ago
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Based on the diagram, which statement explains how energy is conserved during this chemical reaction? D B Potential energy of a
Salsk061 [2.6K]
D hope this helps you
6 0
3 years ago
What is the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO3 by mass)? (a) Outline the steps necess
RoseWind [281]

Answer:

33.8 m

Explanation:

(a) We want to know the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO₃ by mass).

Step 1: Determine the mass of HNO₃ and water in 100 grams of solution.

Step 2: Convert the mass of HNO₃ to moles.

Step 3: Convert the mass of water to kilograms.

Step 4: Calculate the molality.

(b)

Step 1

In 100 g of solution, there are 68.0 g of HNO₃ and 100 g - 68.0 g = 32.0 g of water.

Step 2

The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 68.0 g are:

68.0 g × (1 mol/63.01 g) = 1.08 mol

Step 3

The mass of water is 32.0 g = 0.0320 kg

Step 4

The molality of HNO₃ is:

m = moles of solute / kilograms of solvent

m = 1.08 mol / 0.0320 kg

m = 33.8 m

5 0
3 years ago
Read 2 more answers
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