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3 years ago

Which planetary body was opportunity designed to explore?

Chemistry

1 answer:

11111nata11111 [884]3 years ago

3 0

The rover was designed to explore A.Mars

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Draw the product formed when 2-butanol undergoes reaction with TsCl and Et3N. CH3C6H4SO2Cl.

Pie

Answer:

Explanation:

In organic chemistry, the reaction between 2-butanol with TsCl and Et3N is known as the tosylation of the alcohol hydroxyl group. Alcohol is being changed to tosylate by the use of tosyl chloride under the influence of a base. Tosylation of alcohol is an example of a nucleophilic substitution reaction. From the image attached below, we will see how the reaction between 2-butanol proceed into the product by using tosyl chloride and a base(Et3N).

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4 years ago

Sam toured India with his class. He saw many buildings that reminded him of buildings he saw in Saudi Arabia and in London.

melomori [17]

A) cultural diffusion

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3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!!!

Lyrx [107]

Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Compounds
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})$
[DA] Divide [Cancel out units]: $\displaystyle 5.7015 \ mol \ K_2SO_4$

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

7 0

3 years ago

What type of reactive intermediate is formed in the reaction of an alkene with aqueous acid to give an alcohol?

Mariana [72]

Answer:

The intermediate is carbocation.

Explanation:

The reaction of alkene with an acid to give alcohol is an electrophilic addition reaction.

In electrophilic reaction, the alkene is being attacked by an alkene.

in case of aqueous acid reaction with alkene , the electrophile is [H⁺].

When the proton attacks the alkene it generates carbocation.

The carbocation generated is formed based on stability of carbocation.

The mechanism is shown in the figure.

5 0

4 years ago

When strongly electronegative atoms, like fluorine, bond to atoms with a lower electronegativity, like hydrogen, what's the resu

olganol [36]

When highly electronegative element like oxygen is directly attached to less electronegative element like hydrogen the electrons from less electronegative elements are attracted toward the highly electronegative element, making the less electronegative element deficient in electron density (partial positive) and a partial negative charge on more electronegative element is created. In such situation the intermolecular forces formed are dipole-dipole interactions or hydrogen bond interaction like in HF.

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3 years ago