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Aleks04 [339]
3 years ago
9

Four difference between electrolytic cell and electrochemical cell​

Chemistry
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

Electrochemical cells convert chemical energy into electrical energy or vice versa. Electrolytic cell is a type of electrochemical cell in which electrical energy is converted into chemical energy. ... Electrolytic cells consist of positively charged anode and a negatively charged cathode.

I hope it's help

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Ammonium nitrate, a common fertilizer, is used as an explosive in fireworks and by terrorists. It was the material used in the t
Sladkaya [172]

Explanation:

The given balanced reaction is as follows.

           2NH_{4}NO_{3} \rightarrow 2N_{2} + O_{2} + 4H_{2}O

It is given that mass of ammonium nitrate is 86.0 kg.

As 1 kg = 1000 g. So, 86.0 kg = 86000 g.

Hence, moles of NH_{4}NO_{3} present will be as follows.

      Moles of NH_{4}NO_{3} = \frac{mass given}{\text{molar mass of NH_{4}NO_{3}}}

                                  = \frac{86000 g}{80.043 g/mol}

                                  = 1074.42 mol

Therefore, moles of N_{2}, O_{2} and H_{2}O produced by 1074.42 mole of NH_{4}NO_{3} will be as follows.

  Moles of O_{2} = \frac{1}{2} \times 1074.42 mol

                                = 537.21 mol

Moles of N_{2} = \frac{2}{2} \times 1074.42 mol

                                = 1074.42 mol

Moles of H_{2}O = \frac{4}{2} \times 1074.42 mol

                                = 2148.84 mol

Therefore, total number of moles will be as follows.

          537.21 mol + 1074.42 mol + 2148.84 mol

        = 3760.47 mol

According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.

                       PV = nRT

                     1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex]         (as 307^{o}C = 307 + 273 = 580 K)

                           V = 179066.06 L

Thus, we can conclude that total volume of the gas is 179066.06 L.

3 0
3 years ago
Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he p
Svet_ta [14]
Statement 2 is correct.
solids moving into solution is a physical change as the core structure of the molecules remain the same. evaporation of water and crystallization of salt are both physical changes as well.
The water does not change it's H2O chemical makeup because salt was dissolved into it.
5 0
4 years ago
Read 3 more answers
What is the last element in the periodic table?
borishaifa [10]

Answer:

Ununoctium

Explanation:

It's at the very end of the periodic table

6 0
3 years ago
Read 2 more answers
What is the percentage of oxygen in air<br> ASAP...​
abruzzese [7]

Explanation:

21 % of oxygen is present in air .

hope it is helpful to you

3 0
3 years ago
Hydrogen sulfide (H2S) is a gas that smells like rotten eggs. It can be produced by bacteria in your mouth and contributes to ba
Doss [256]

Answer:

See explanation.

Explanation:

Hello!

In this case, we consider the questions:

a. Ideal gas at:

 i. 273.15 K and 22.414 L.

 ii. 500 K and 100 cm³.

b. Van der Waals gas at:

 i. 273.15 K and 22.414 L.

 ii. 500 K and 100 cm³.

Thus, we define the ideal gas equation and the van der Waals one as shown below:

P^{id}=\frac{nRT}{V}\\\\ P^{vdW}=\frac{RT}{v-b}-\frac{a}{v^2}

Whereas b and a for hydrogen sulfide are 0.0434 L/mol and 4.484 L²*atm / mol² respectively, therefore, we proceed as follows:

a.

 i. 273.15 K and 22.414 L.

P^{id}=\frac{1.00mol*0.08206\frac{atm*L}{mol*K}*273.15K}{22.414L}=1 .00 atm

 ii. 500 K and 100 cm³ (0.1 L).

P^{id}=\frac{1.00mol*0.08206\frac{atm*L}{mol*K}*500K}{0.100L}=410.3 atm

b.

 i. 273.15 K and 22.414 L: in this case, v = 22.414 L / 1.00 mol = 22.414 L/mol

P^{vdW}=\frac{0.08206\frac{atm*L}{mol*K}*273.15K}{22.414L/mol-0.0434L/mol}-\frac{4.484 atm*L^2/mol^2}{(22.414L/mol)^2}=0.993atm

 ii. 500 K and 100 cm³: in this case, v = 0.1 L / 1.00 mol = 0.100 L/mol

P^{vdW}=\frac{0.08206\frac{atm*L}{mol*K}*500K}{0.100L/mol-0.0434L/mol}-\frac{4.484 atm*L^2/mol^2}{(0.100L/mol)^2}=276.5atm

Whereas we can see a significant difference when the gas is at 500 K and occupy a volume of 0.100 L.

Best regards!

5 0
3 years ago
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