F(x) = g(x)
3(2) - 4 = (2)² - 2
6 - 4 = 4 - 2
2 = 2
I just substituted all the values in the domain to see which one would work. That's not really the quickest way but that's the only way I know
R=S*0.5^(t/8)
<span>R is the remaining amount </span>
<span>S is the starting amount (500) </span>
<span>0.5^ is for the HALF in half-life </span>
<span>t/8 show that every 8 ts (every 8 hours), it will be halved once </span>
<span>...so plug in 500mg for the general solution... </span>
<span>R=(500)*(0.5)^(t/8) </span>
<span>... plug in 24h to solve for after 24h </span>
<span>R=(500)*(0.5)^(24/8) </span>
<span>R=(500)*(0.5)^(3) </span>
<span>R=(500)*(0.125) </span>
<span>R=(0.0625) </span>
<span>...therefore there with be 0.0625 mg of the dose remaining</span>
Pemdas
Parentheses
Answer: -11
Answer:
No. It is not a good idea. She should write things she is good at or has done in the past. Leaving it blank will help not Isabella.
Answer:
66 girls
Step-by-step explanation:
Givens:
●120% boys of girls
▪︎1.2 × g
☆when g is the number of girls
●80 boys
▪︎meaning you can set up a proportion
Solving:
g × 1.2 = 80
g=80/1.2
g=66.66
So, since you can't go over percent, the answer is 66.
Checking:
g × 1.2 = 80
66 × 1.2 = 80
80=80✅
