Answer:
(a) 7.5 seconds
(b) The horizontal distance the package travel during its descent is 1737.8 ft
Step-by-step explanation:
(a) The given function for the height of the object is s = -16·t² + v₀·t + s₀
The initial height of the object s₀ = 900 feet
The initial vertical velocity of the object v₀
= 0 m/s
The time it takes the package to strike the ground is found as follows;
0 = -16·t² + 0×t + 900
900 = 16·t²
t² = 900/16 = 62.25
t = √62.25 = 7.5 seconds
(b) Given that the horizontal velocity of the package is given as 158 miles/hour, we have
158 miles/hour = 231.7126 ft/s
The horizontal distance the package covers in the 7.5 second of vertical flight = 231.7126 ft/s × 7.5 s = 1737.8445 feet = 1737.8 ft to one decimal place
The horizontal distance the package travel during its descent = 1737.8 ft.
Answer:
Step-by-step explanation:
12,800 written as 1.28 x 104 in scientific notation
yards/costumes:16/(5/2) = X/(19/2)
Cross multiply.
(5/2)x = 152
Multiply both sides by 2/5.
x = 101 1/3 yards
Answer:
9
Step-by-step explanation:
substitute the x which is x= 2, so
f(2)= (2+1)^2
=(3)^2
=9