All categories

3 years ago

Divide. Express your answer in simplest form.

Mathematics

1 answer:

UkoKoshka [18]3 years ago

7 0

1 7/11 <span>÷ 2 1/2</span>

= 18/11 ÷ 5/2

= (18 × 2) / (5 × 11)

= 36/55

(36/55 is already in simple form)

You might be interested in

What is the surface area of the figure?

Whitepunk [10]

The answer i c,because if u sum it up,u get that

3 0

3 years ago

A cut was made on each solid parallel to its base. Will the cut form a two-dimensional figure that is exactly the same shape as

ivolga24 [154]

Answer:

Step-by-step explanation: yes yes no yes no I think. I think it’s no for cylinder and cube bc if u cut them, it’ll be the same shape but also the same size

8 0

3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago

Let f be defined as shown on the graph. Which statement is true?

satela [25.4K]

The inverse of f does NOT exist. The reason why is because the function fails the horizontal line test. Recall that the horizontal line test is a test where you try to see if you can pass a single horizontal line through more than one point on the function curve. If you can get the horizontal line to pass through more than one point, then it fails the test. It's very similar to the vertical line test.

4 0

3 years ago

Find the value of x for which the function below is maximum

timurjin [86]

Answer:

x = $\frac{1}{2}$