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Anon25 [30]
3 years ago
5

Do you think a hurricane can be considered to be a heat machine? Why?

Physics
2 answers:
Colt1911 [192]3 years ago
8 0

Answer:

YES

Explanation:

When the surface water is warm, the storm sucks up heat energy from the water, just like a straw sucks up a liquid. This creates moisture in the air. If wind conditions are right, the storm becomes a hurricane. This heat energy is the fuel for the storm.  So therefore yes i do

Leona [35]3 years ago
5 0

Answer:

No

Explanation:

Hurricanes always do not bring heat. For example, Hurricane Sandy brought snow.

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Naddika [18.5K]

Answer:

moving

Explanation:

They've been moving for thousands and thousands of years. Millions of years ago there was a land called Pangea that seperated into the continents we see today.

7 0
3 years ago
Read 2 more answers
A 3.8 car is traveling at 19 m/s . What is it's momentum?
pashok25 [27]

The Momentum Calculator uses the formula p=mv, or momentum (p) is equal to mass (m) times velocity (v).

8 0
2 years ago
Show that liquid pressure is directly<br>proportional to height of liquid in a vessel.​
Norma-Jean [14]

Answer:

P=F/A where F is the weight of the water and A is the area on which it is resting. The weight of the water is mg. The mass of the water is dv where d is the density and v is the volume. Finally, the volume of the water in a vessel is equal to the area of the base of the vessel times the height of the vessel. (v=Ah)

Plugging everything in we get:

P = dAhg/A

So

P=dhg

So we have shown that liquid pressure is directly  proportional to height of liquid in a vessel.​

7 0
3 years ago
Draw the graphs for exothermic and endothermic reactions Label: axes, reactants, products, Energy of reaction, heat energy chang
nikdorinn [45]

Answer:

axes, reactants, products, Energy of reaction, heat energy

Explanation:

axes, reactants, products, Energy of reaction, heat energyaxes, reactants, products, Energy of reaction,grreactantsaphs heat energy

3 0
3 years ago
A light source radiates 60.0 W of single-wavelength sinusoidal light uniformly in all directions. What is the amplitude of the m
Anna35 [415]

To solve this problem it is necessary to take into account the concepts of Intensity as a function of Power and the definition of magnetic field.

The intensity depending on the power is defined as

I = \frac{P}{4\pi r^2},

Where

P = Power

r = Radius

Replacing the values that we have,

I = \frac{60}{(4*\pi (0.7)^2)}

I = 9.75 Watt/m^2

The definition of intensity tells us that,

I = \frac{1}{2}\frac{B_o^2 c}{\mu}

Where,

B_0 =Magnetic field

\mu = Permeability constant

c = Speed velocity

Then replacing with our values we have,

9.75 = \frac{Bo^2 (3*10^8)}{(4\pi*10^{-7})}

Re-arrange to find the magnetic Field B_0

B_o = 2.86*10^{-7} T

Therefore the amplitude of the magnetic field of this light is B_o = 2.86*10^{-7} T

6 0
3 years ago
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