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2 years ago

5

Do you think a hurricane can be considered to be a heat machine? Why?

2 answers:

Colt1911 [192]2 years ago

8 0

Answer:

YES

Explanation:

When the surface water is warm, the storm sucks up heat energy from the water, just like a straw sucks up a liquid. This creates moisture in the air. If wind conditions are right, the storm becomes a hurricane. This heat energy is the fuel for the storm. So therefore yes i do

Leona [35]2 years ago

5 0

Answer:

No

Explanation:

Hurricanes always do not bring heat. For example, Hurricane Sandy brought snow.

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Based on the map, which area has a scarcity of fresh water?

Westkost [7]

Answer:

North Africa

Explanation:

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6 0

2 years ago

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A motorboat is moving at 4.0 m/s when it begins to accelerate at 1.0 m/s2. To the nearest tenth of a second, how long does it ta

vaieri [72.5K]

Answer:

13 sec

Explanation:

Hello

by definition the acceleration is a vector derived magnitude that indicates the speed variation per unit of time

$a=\frac{V_{f}-V_{i}}{t_{f}-t_{i}}\\a(t_{f}-t_{i})={V_{f}-V_{i} }}\\t_{f}-t_{i}=\frac{V_{f}-V_{i}}{a} \\\\t_{f}=\frac{V_{f}-V_{i}}{a}+t_{i} \\\\$

Let

Vi=4.0 m/s

a=1.0 m/s2

Vf=17.0 m/s

ti= (0)sec

t2= unknown

$t_{f}=\frac{V_{f}-V_{i} }{a}+t_{i}\\t_{f}=\frac{17-4 }{1}+0\\t_{f}=\ 13\ sec\\$

Answer: 13 sec

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8 0

3 years ago

Electromagnetic waves are ____________ (one thousand/one million) times faster than sound.

vesna_86 [32]

Answer:

one million

Explanation:

3 0

3 years ago

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Calculate the density of gold if 96500kg mass of gold is adjusted in the volume of 5m cube

PSYCHO15rus [73]

Answer:

96500÷5=19300

Explanation:

96500÷5=19300

6 0

3 years ago

An unpolarized light beam with intensity I0 is first passed through an ideal polarizer. At this instant, the light is polarized.

-BARSIC- [3]

Answer:

The intensity of the emerging light reduced to 25%

Explanation:

Given :

Unpolarized light intensity = $I_{o}$

Initial polarizer angle = 0°

Final polarizer angle between optic axis and transmission axis = 45°

Unpolarized light passes through first polarizer the intensity reduces to half.

after second polarizer the intensity is half till the last polarizer,

$I_{3} = \frac{I_{o} }{2} \cos^{2} 45$

$I_{3} = \frac{I_{o} }{4}$

Therefore, the intensity of the emerging light reduced to 25%

7 0

3 years ago