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3 years ago

Explain how a parachute works

2 answers:

5 0

As the skydiver and the parachute fall, the air around them fills the inside of the parachute and causes them both to fall at a much slower rate than normal. The large surface area, and the light weight of the parachute allow it to fall slowly.

Shtirlitz [24]3 years ago

4 0

A parachute increases air friction, thus reducing falling speed.

Indeed, the air friction is roughly proportional to the surface of the object falling down; the parachute tremendously increases that surface.

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Using only one management style with all people is the most effective leadership technique for any organization.

Softa [21]

the answer for this is false

4 0

3 years ago

Another engineer is running a series of experiments with hydraulic systems. If she doubles the area of the input piston, what ha

Zepler [3.9K]

Answer:

The pressure remains the same.

F = P * A the amount of force transmitted would double if only the input area is changed. Pressure is the same at all points in the system.

7 0

3 years ago

Is an object moving in uniform circular motion accelerating?

dexar [7]

Yes.

-- 'Acceleration' does NOT mean 'speeding up'.
It means ANY change in the speed OR direction of motion ...
speeding up, slowing down, or turning.

-- If an object is NOT moving in straight line at constant speed,
then its motion is accelerated.

-- In circular motion, or even just going around a curve,
the object is accelerating, because its direction is constantly
changing, even if its speed is constant.

8 0

3 years ago

Is this statement true or false concerning squall line thunderstorm development? These often form ahead of the advancing front b

Pavlova-9 [17]

Answer: The following statement is true about squall line thunderstorm development: These often form ahead of the advancing front but rarely behind it because lifting of warm, humid air and the generation of a squall line usually occur in the warm sector ahead of an advancing cold front. Behind a cold front, the air motions are usually downward, and the air is cooler and drier.

An upper-level wave, accountable for the fabrication of a squall line, extend in front of and backside a cold front, the air backside the front is cold, steady and settling while the air ahead of the front is hot and co-seismic.

3 0

3 years ago

A small block of mass m1 = 0.4 kg is placed on a long slab of mass m2 = 2.8 kg. Initially, the slab is stationary and the block

mel-nik [20]

Answer:

v₁ = 0.375 m / s , x = 0.335 m

Explanation:

Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.

We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.

initial moment. Right at the start of the movement

p₀ = m v₀ + 0

final moment. Just when it comes to equilibrium

$p_{f}$ = (m + M) v₁

how the forces are internal

p₀ =p_{f}

m v₀ = (m + M) v₁

v₁ = m /m+M v₀

let's calculate

v₁ = 0.4 /(0.4 + 2.8) 3

v₁ = 0.375 m / s

Let's apply Newton's second law to the Block, to find the friction force

Y axis

N - W = 0

N = W

N = m g

where m is the mass of the block

the friction force has the formula

fr = μ N

fr = μ m g

We apply Newton's second law to slab

X axis

fr = M a

where M is the mass of the slab

μ m g = M a

a = μ g m / M

let's calculate

a = 0.15 9.8 0.4 / 2.8

a = 0.21 m / s²

With kinematics we can find the position

v²= v₀²+2 a x

as the slab is initially at rest, its initial velocity is zero

v² = 2 a x

x = v2 / 2a

let's calculate

x = 0.375²/2 0.21

x = 0.335 m

4 0

3 years ago