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4 years ago

Explain how a parachute works

2 answers:

5 0

As the skydiver and the parachute fall, the air around them fills the inside of the parachute and causes them both to fall at a much slower rate than normal. The large surface area, and the light weight of the parachute allow it to fall slowly.

Shtirlitz [24]4 years ago

4 0

A parachute increases air friction, thus reducing falling speed.

Indeed, the air friction is roughly proportional to the surface of the object falling down; the parachute tremendously increases that surface.

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Which of the following is not a valid conversion factor?

kykrilka [37]

The third option is wrong

8 0

3 years ago

Inertia is responsible for :

DENIUS [597]

B. the reason we must wear seat belts

8 0

3 years ago

Read 2 more answers

Asteroids are between 1000 km and less than 10 m in diameter. What is the diameter of most asteroids?

e-lub [12.9K]

This question needs research to be answered. From the given information alone it can't be answered without making wild assumptions.

Ideally, you need to take a look at a distribution (or a histogram) of asteroid diameters, identify the "mode" of such a distribution, and find the corresponding diameter. That value will be the answer.

I am attaching one such histogram on asteroid diameters from the IRAS asteroid catalog I could find online. (In order to get a single histogram, you need to add the individual curves in the figure first). Eyeballing this sample, I'd say the mode is somewhere around 10km, so the answer would be: the diameter of most asteroid from the IRAS asteroid catalog is about 10km.

7 0

3 years ago

70.5

ra1l [238]

Answer:5000000000hertz

Explanation:

Wavelength=6cm=6/100 m=0.06m

Frequency=velocity/wavelength

Frequency=(3×10^8)÷0.06

Frequency=5000000000 hertz

5 0

3 years ago

An assault rifle fires an eight-shot burst in 0.40 s. Each bullet has a mass of 7.5 g and a speed of 300 m/s as it leaves the gu

myrzilka [38]

Answer:

The average recoil force on the gun during that 0.40 s burst is 45 N.

Explanation:

Mass of each bullet, m = 7.5 g = 0.0075 kg

Speed of the bullet, v = 300 m/s

Time, t = 0.4 s

The change in momentum of an object is equal to impulse delivered. So,

$F\times t=mv\\\\F=\dfrac{mv}{t}$

For 8 shot burst, average recoil force on the gun is :

$F=\dfrac{8mv}{t}\\\\F=\dfrac{7.5}{1000}\cdot\dfrac{300}{0.4}\cdot8\\\\F=45\ N$

So, the average recoil force on the gun during that 0.40 s burst is 45 N.

5 0

3 years ago