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4 years ago

Explain how a parachute works

2 answers:

5 0

As the skydiver and the parachute fall, the air around them fills the inside of the parachute and causes them both to fall at a much slower rate than normal. The large surface area, and the light weight of the parachute allow it to fall slowly.

Shtirlitz [24]4 years ago

4 0

A parachute increases air friction, thus reducing falling speed.

Indeed, the air friction is roughly proportional to the surface of the object falling down; the parachute tremendously increases that surface.

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Select all the correct answers. The eight planets in alphabetical order are Earth, Jupiter, Mars, Mercury, Neptune, Saturn, Uran

Rainbow [258]

Answer:

The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars. After an asteroid belt comes the outer planets, Jupiter, Saturn, Uranus and Neptune

Explanation:

4 0

3 years ago

Read 2 more answers

If 31.25

valentina_108 [34]

<span>1 C = 6.24150965(16)×10^18 electrons

31.25 x 10^18 electrons / (6.24150965(16)×10^18 electrons / C) = 5.007 Coulombs

</span><span>I hope this helps. </span>

4 0

3 years ago

Read 2 more answers

David rowed a boat upstream for three miles and then returned to point he started from. The entire journey took four hours. The

frez [133]

Upstream speed = S - 1
Downstream speed = S + 1

Average speed = total distance / total time

Average speed = (S - 1) + (S + 1) / 2
= S

S = 6 miles / 4 hours
S = 1.5 miles per hour

4 0

3 years ago

A 15kg hoop with a radius of 3 m is rolling at on a level surface when it reaches a 25 degree incline. If it reaches a height of

dimulka [17.4K]

The initial velocity of the hoop is determined as 8.854 m/s.

<h3>Conservation of energy</h3>

The initial velocity of the hoop can be determined from the principle of conservation of energy.

Final potential energy = Initial kinetic energy

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

2gh = v²

√2gh = v

√(2 x 9.8 x 4) = v

8.854 m/s = v

Thus, the initial velocity of the hoop is determined as 8.854 m/s.

Learn more about initial velocity here: brainly.com/question/19365526

#SPJ1

4 0

2 years ago

The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of t

Veronika [31]

Answer:

the cart's speed at point B is 15.72 ft/s

Explanation:

Given the data in the question;

The car travels from point A to C in 3.00 s, its average acceleration $a_{avg}$ will be;

$a_{avg}$ = [ $V_{c}$ - $V_{A}$ ] / Δt

$V_{c}$ is 17.4 ft/s, $V_{A}$ is 13.2 ft/s and Δt is 3.00 s

so we substitute

$a_{avg}$ = [17.4 - 13.2] / 3

$a_{avg}$ = 4.2 / 3

$a_{avg}$ = 1.4 ft/s²

so average acceleration of the cart between the points A and B is 1.4 ft/s²

The instantaneous value of the velocity of the cart at point B will be;

$a_{avg}$ = Δv / Δt

now substitute [ $V_{c}$ - $V_{B}$ ] for Δv and t' for Δt

$a_{avg}$ = [ $V_{c}$ - $V_{B}$ ] / t'

$V_{B}$ = $V_{c}$ - $a_{avg}$ ( t' )

so we substitute 17.4 ft/s for $V_{c}$ , 1.20 s for t' and $a_{avg}$ = 1.4 ft/s²

$V_{B}$ = 17.4 - (1.4 × 1.20)

$V_{B}$ = 17.4 - 1.68

$V_{B}$ = 15.72 ft/s

Therefore, the cart's speed at point B is 15.72 ft/s

5 0

3 years ago