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3 years ago

When hydrogen chloride is added to sodium hydroxide, it will produce water and what?

Physics

2 answers:

sveticcg [70]3 years ago

7 0

It will produce water and salt, as they are an acid and a base so a neutralization reaction will take place.

Hope it helps..

IRINA_888 [86]3 years ago

3 0

Answer: HCl+H2O→H3O++Cl- Hydrochloric acid in water increases the concentration of H3O+ ions and is therefore an acid. NaOH+H2O→Na++OH- Sodium hydroxide in water increases the concentration of OH- ions and is therefore a base.

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Why does the chlorine atom have a partial negative charge in a molecule of hydrogen chloride?

bulgar [2K]

Answer:The molecule is represented by the conventional Lewis structure, even though the shared electron pair is associated to a larger extent with chlorine than with hydrogen. The unequal sharing of the bonding pair results in a partial negative charge on the chlorine atom and a partial positive charge on the hydrogen atom.

Explanation:

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2 years ago

A stockroom worker pushes a box with mass 16.8 kg on a horizontal surface with a constant speed of 3.50 m/s. The coefficient of

nignag [31]

Answer:

a) $fr =\mu N= 0.2*164.64 N= 32.928 N$

And we need a force $F> 32.928 N[tex]b) [tex] d = \frac{-v^2_i}{2a}= \frac{-(3.5m/s)^2}{-2*1.96 m/s^2}= 3.13m$

Explanation:

Part a

For this case we have the following forces illustrated on the figure attached.

If we analyze on the x axis we just have two forces, fr the friction force and F the force to mantain the movement.

So we need this condition to satisfy the movement:

$F > fr$

If we analyze the forces on the y axis we have this:

$\sum Fy= ma_y = 0$

Because we have constant speed for this reason the acceleration is 0

$N -W = 0$

$N = mg = 16.8Kg * 9.8 \frac{m}{s^2}= 164.64 N$

And by definition the friction force is defined as: $fr = \mu N$

So then the friction force would be:

$fr =\mu N= 0.2*164.64 N= 32.928 N$

And we need a force $F> 32.928 N$

Part b

For this case we assume that F =0 and we have a friction force of 32.928 N.

From the second law of Newton we have:

$F = ma$

$a = \frac{F}{m}= -\frac{fr}{m}= -\frac{32.928 N}{16.8 Kg}= -1.96m/s^2$

vf =0 (final velocity, rest at the end) and vi = 3.5 m/s.

And we can find the time for the motion like this:

$vf = v_i + at$

$t = \frac{-v_i}{a}= \frac{-3.5 m/s}{-1.96 m/s^2}= 1.78 s$

And then we can find the distance from the following formula:

$v^2_f= v^2_i + 2a d$

$d = \frac{-v^2_i}{2a}= \frac{-(3.5m/s)^2}{-2*1.96 m/s^2}= 3.13m$

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3 years ago

An airplane whose air speed is 527 mi/hr covers a distance of 907 miles in 2.25 hrs. How strong was the head wind against it?

melamori03 [73]

Answer:

cda

Explanation:

csa

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Answer: The English origin was the largest

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