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lilavasa [31]
3 years ago
5

Choose only one correct option. Explanation needed.

Physics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

\large \boxed{\mathrm{C. \  \  \frac{500}{7 \times 15  \times 8} \ g/cm^3 }}

Explanation:

\displaystyle \sf Density = \frac{mass}{volume}

\displaystyle \rho = \frac{m}{V}

\sf mass=500 \ g

\sf volume \ of \ a \ cuboid=width  \times length  \times height=( 7 \times 15 \times 8) \ cm^3

\displaystyle \rho = \frac{500}{7 \times 15  \times 8}

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A snowball is thrown with an initial x velocity of 7.5 m/s and an initial y velocity of 8.4 m/s . Part A How much time is requir
elena55 [62]

In order to calculate the time taken by the snowball to reach the highest point in its journey, we need to consider the variables along the y-direction.

Let us list out what we know from the question so that we can decide on the equation to be used.

We know that Initial Y VelocityV_{iy} = 8.4 m/s

Acceleration in the Y direction a_{y} = -9.8 m/s^{2}, since the acceleration due to gravity points in the downward direction.

Final Y Velocity V_{fy} = 0 because at the highest point in its path, an object comes to rest momentarily before falling down.

Time taken t = ?

From the list above, it is easy to see that the equation that best suits our purpose here is V_{fy} = V_{iy} + a_{y}t

Plugging in the numbers, we get 0 = 8.4 - (9.8)t

Solving for t, we get t = 0.857 s

Therefore, the snowball takes 0.86 seconds to reach its highest point.

8 0
3 years ago
In a microwave oven, electrons describe circular motion in a magnetic field within a special tube called amagnetron; as you'll l
QveST [7]

Answer:

The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

Explanation:

Given that,

Diameter = 2.62 mm

Frequency = 2.15 GHz

(A). We need to calculate the magnetic field strength

Using formula of the magnetic field strength

B=\dfrac{2\pi mf}{e}

Where, f = frequency

e = charge of electron

Put the value into the formula

B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}

B=0.077\ T

(B). We need to calculate the energy of electron

Using formula of energy

E=\dfrac{1}{2}m(r\omega)^2

E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2

E=1.4249\times10^{-16}\ J

The energy in eV

1 eV=1.6\times10^{-16}\ J

E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}

E=0.8906\ eV

Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

5 0
3 years ago
Question 1 of 5
Elina [12.6K]

Answer:

solar energy warms most of the earths surface

3 0
2 years ago
Define static electricity and ohms law​
iVinArrow [24]

Answer:

Static electricity : is a familiar electric phenomenon in which charged particles are transferred from one body to another

Ohm's law : states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance

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2 years ago
a radio antenna broadcasts a 1.0 MHz radio wav e with 21 kW of power. Assume that the radiation is emitted uniformly in all dire
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Answer:

I=2.67\times 10^{-6}\ W/m

Explanation:

Given that,

Frequency of a radio antenna is 1 MHz

Power, P = 21 kW

We need to find the the waves intensity 25 km from the antenna . The object emits intenisty evenly in all direction. It can be given by :

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So, the wave intensity 25 km from the antenna is 2.67\times 10^{-6}\ W/m.

5 0
3 years ago
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