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4 years ago

1. All matter is composed of atoms or molecules that have energy of motion, which

Chemistry

2 answers:

Roman55 [17]4 years ago

8 0

Answer:

C Kinetic Energy.

Explanation:

Kinetic energy is energy of motion.

Setler [38]4 years ago

5 0

Potential energy i think?

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100 PTS+BRAINILIEST: Why does it get colder as you go higher through the atmosphere, if you are getting closer to the sun??

sattari [20]

Answer/Explanation:

Heat from the sun hits the ground and is absorbed. The higher you go, it gets more colder due to the fact that the air doesn't hold onto the radiation as it goes straight through the ground, which is why the top of mountains are very cold, and people are able to die in minutes.

8 0

2 years ago

Read 2 more answers

an aqeous solution of oxalic acid h2c2o4 was prepared by dissolving a 0.5842g of solute in enough water to make a 100 ml solutio

vampirchik [111]

The question is incomplete, here is the complete question:

An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?

<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of oxalic acid = 0.5842 g

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of oxalic acid solution}=\frac{0.5842\times 1000}{90\times 100}\\\\\text{Molarity of oxalic acid solution}=0.0649M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated oxalic acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted oxalic acid solution

We are given:

$M_1=0.0649M\\V_1=10mL\\M_2=?M\\V_2=250.0mL$

Putting values in above equation, we get:

$0.0649\times 10=M_2\times 250.0\\\\M_2=\frac{0.0649\times 10}{250}=0.0026M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of oxalic acid solution = 0.0026 M

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0026=\frac{\text{Mass of oxalic acid solution}\times 1000}{90\times 100}\\\\\text{Mass of oxalic acid solution}=\frac{0.0026\times 90\times 100}{1000}=0.0234g$

Hence, the mass of oxalic acid in final solution is 0.0234 grams

6 0

4 years ago

What must be true about a substance that is being dissolved by water?

Elena-2011 [213]

Water is always the solvent

7 0

4 years ago

Three positive charges lie on the x axis: q1 = 1 × 10−8 C at x1 = 1 cm, q2 = 2 × 10−8 C at x2 = 2 cm, and q3 = 3 × 10−8 C at x3

NARA [144]

Answer: Option (4) is the correct answer.

Explanation:

Relation between potential energy and charge is as follows.

U = $\frac{1}{4 \pi \epsilon_{o}}[\frac{q_{1}q_{2}}{r_{12}} + \frac{q_{2}q_{3}}{r_{23}} + \frac{q_{3}q_{1}}{r_{31}}]$

As it is given that $q_{1} = 1 \times 10^{-8} C$ , $q_{2} = 2 \times 10^{-8} C$ , and $q_{3} = 3 \times 10^{-8} C$ .

Distance between the charges = 1 cm = $1 \times 10^{-2} m$ (as 1 cm = 0.01 m)

Hence, putting these given values into the above formula as follows.

U = $\frac{1}{4 \pi \epsilon_{o}}[\frac{q_{1}q_{2}}{r_{12}} + \frac{q_{2}q_{3}}{r_{23}} + \frac{q_{3}q_{1}}{r_{31}}]$

= $9 \times 10^{9} [\frac{1 \times 10^{-8} \times 2 \times 10^{-8}}{10^{-2}} + \frac{2 \times 10^{-8} \times 3 \times 10^{-8}}{10^{-2}} + \frac{3 \times 10^{-8} \times 1 \times 10^{-8}}{10^{-2}}]$

= $9 \times 10^{9} [2 + 6 + 1.5]$

= $85.5 \times 10^{-5}$ J

= 0.00085 J

Thus, we can conclude that the potential energy of this arrangement, relative to the potential energy for infinite separation, is about 0.00085 J.

8 0

3 years ago

A copper wire is 44.85 cm long and weighs 1.521 g. The density of copper is 8.933 g/cm3.

PolarNik [594]

Answer:

i am so sorry

Explanation:

7 0

3 years ago