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3 years ago

A copper wire is 44.85 cm long and weighs 1.521 g. The density of copper is 8.933 g/cm3.

Chemistry

1 answer:

PolarNik [594]3 years ago

7 0

Answer:

i am so sorry

Explanation:

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Water ionizes by the equationH2O(l)⇌H+(aq)+OH−(aq)The extent of the reaction is small in pure water and dilute aqueous solutions

tia_tia [17]

Explanation:

$H_2O(l)\rightleftharpoons H^+(aq)+OH^-(aq)$

The value of $K_w$ :

$K_w=[H^+][OH^-]$

a. pOH = 3.51

The sum of pH and pOH is equal to 14.

pH + pOH = 14 (at 25°C)

pH = 14 - 3.51 = 10.49

The pH of the solution is defined as negative logarithm of hydrogen ion concentration in solution.

$pH=-\log[H^+]$

$10.49=-\log[H^+]$

$[H^+]=3.2\times 10^{-11}$

$3.2\times 10^{-11} M$ is the $H^+$ concentration for an aqueous solution with pOH = 3.51 at 25°C.

At a certain temperature, the pH of a neutral solution is 7.56.

Neutral solution means that concentration of hydrogen ion and hydroxide ions are equal.

$[H^+]=[OH^-]$

$7.56=-\log[H^+]$

$[H^+]=2.754\times 10^{-8} M$

The value of $K_w$ at at this temperature:

$K_w=[H^+][OH^-]$

$K_w=[H^+][H^+]$

$K_w=(2.754\times 10^{-8})^2=7.6\times 10^{-16}$

The value of $K_w$ at at this temperature is $7.6\times 10^{-16}$ .

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4 years ago

Which argument is correct

torisob [31]

Answer:

The first agrument.

Explanation:

Because only heat can be transfered. Thats why if you put something hot in a refridgerator the heat energy will go off in the fridge and powers the cold energy. Im pretty sure this is right this is what my teachers tought me so i hope they right

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2 years ago

MULTIPLE CHOICE QUESTION

Tpy6a [65]

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3 years ago

A testable question is one that _____.

cestrela7 [59]

Answer:

One that “Can be answered by conducting an experiment”

Explanation:

8 0

3 years ago

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A 2.35 g sample of an unknown gas at 55 ∘C and 1.05 atm is stored in a 1.85 L flask.

lbvjy [14]

Answer:

Molar mass = 32.64 g / mol.

The density of gas is 1.3 × 10⁻³g/mL.

Explanation:

Given data:

Mass of sample = 2.35 g

Pressure = 1.05 atm

Volume = 1.85 L (1.85 × 1000 = 1850 ml)

Temperature = 55 °C (55+ 273.15 = 328.15 K)

Density = ?

Formula:

d = m/ v

The volume of flask would be the volume of gas.

d = 2.35 g / 1850 mL = 0.0013 g/mL or 1.3 × 10⁻³g/mL

The density of gas is 1.3 × 10⁻³g/mL.

Molar mass:

Now we will calculate the moles of a gas first in order to find the molar mass of a gas.

Formula:

PV =nRT

n = number of moles.

n = PV / RT

n = 1.05 atm × 1.85 L / 0.0821 atm. dm³. K⁻¹ . mol⁻¹ × 328.15 K

n = 1.9425 atm . L / 26.941115 atm . dm.³mol⁻¹

n = 0.072 mol

Now we will find the molar mass.

Number of moles = mass / molar mass

0.072 mol = 2.35 g / molar mass

Molar mass = 2.35 g / 0.072 mol

Molar mass = 32.64 g / mol

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3 years ago

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