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lana66690 [7]
3 years ago
8

How many moles of HCl are needed to react with 0.87 mol Al?

Chemistry
1 answer:
WARRIOR [948]3 years ago
5 0
The answer is ( 2.6 mol HCl )
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What is the atomic weight of a hypothetical element consisting of two isotopes, one with mass = 64.23 amu (26.0%), and one with
matrenka [14]
I think it should be A or D
8 0
3 years ago
Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

k_1=1.5\times 10^3s^{-1}  

T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

T_2=298.15\ K

So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0
3 years ago
What is the temperature at which something boils? A chemical change or property or a physical change or property?
DerKrebs [107]
The boiling point of a substance is a physical property. A physical property of a material or substance is one that can be observed without changing or altering the composition of the material. Examples are mass, Density, Color, solubility, boiling point, melting point . A chemical property of a substance is one that describes how the material changes into a completely different substance and is observed only during a chemical reaction. Examples of chemical properties include types of chemical bonds, heat of combustion, reactivity with other metals, oxidation state and enthalpy of formation.
8 0
3 years ago
Select all of the following equations that represent an exothermic reaction.
skelet666 [1.2K]
Exothermic reactions:

1)  release heat to the surroundings

2) the change of enthalpy, ΔH, is negative: ΔH < 0

3) the temperature of the system increases

With that you can conclude about every equation given:

<span>NH3(g) + 12.0 kcal → ½N2(g) + 3/2 H2(g) : is not exothermic because heat in the side of the reactants means that heat is being used, not released.

C(graphite) → C(diamond), ΔH = - 0.45 kcal : is exothermic because ΔH is negative

C + 2S → CS2, ΔH = 27,550 cal: is not exothermic because ΔH is positive

CH4 + 2O2 → CO2 + 2H2O + 212,800 cal : is exothermic because heat appears as a product of the reaction, which means that it is released.

2H2O → 2H2 + O2, ΔH = +58 kcal : is not exothermic because ΔH is positive.</span>


3 0
3 years ago
HELP ME PLEASE Im stuck I said d but please make sure
morpeh [17]

Answer:

The fourth one.

Explanation:

The fourth graph shows an object speeding up ( accelerating ) coz the velocity (tangent at the curve ) at every point is different, hence denoting an acceleration.

3 0
3 years ago
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