A circuit breaker is rated for a current of 25 a rms at a voltage of 240 v rms. (a) what is the largest value of imax that the b
reaker can carry?
1 answer:
The largest value of current that the breaker can carry = Imax=35.4A
Explanation:
Rms value of current= Irms= 25 A
The rms current and the maximum current are related as
Imax= √2 Irms
Imax=√2 (25)
Imax=35.4 A
Thus the maximum current carried by the breaker= 35.4 A
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