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3 years ago

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A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D

along the direction of its motion.
Part A: Find vf, the final speed of the particle after it has traveled a distance D. Express the final speed in terms of vi, M, F, and D.

1 answer:

LenaWriter [7]3 years ago

6 0

Answer:

vf = √(vi²+2*(F/m)*D)

Explanation:

Given

Mass of the particle: M

Initial speed of the particle: vi

Force: F

Distance: D

We can apply the formula

F = M*a ⇒ a = F/m

then we use the equation

vf = √(vi²+2*a*D)

⇒ vf = √(vi²+2*(F/m)*D)

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g A cylinder of mass m is free to slide in a vertical tube. The kinetic friction force between the cylinder and the walls of the

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Answer:

The vertical distance is $d = \frac{2}{k} *[mg + f]$

Explanation:

From the question we are told that

The mass of the cylinder is m

The kinetic frictional force is f

Generally from the work energy theorem

$E = P + W_f$

Here E the the energy of the spring which is increasing and this is mathematically represented as

$E = \frac{1}{2} * k * d^2$

Here k is the spring constant

P is the potential energy of the cylinder which is mathematically represented as

$P = mgd$

And

$W_f$ is the workdone by friction which is mathematically represented as

$W_f = f * d$

So

$\frac{1}{2} * k * d^2 = mgd + f * d$

=> $\frac{1}{2} * k * d^2 = d[mg + f ]$

=> $\frac{1}{2} * k * d = [mg + f ]$

=> $d = \frac{2}{k} *[mg + f]$

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3 years ago

A transformer is intended to decrease the value of the alternating current from 500 amperes to 25 amperes. The primary coil cont

EastWind [94]

Answer:

The number of turns in secondary coil is 4000

Explanation:

Given:

Current in primary coil $I_{P} = 500$ A

Current in secondary coil $I_{S} = 25$ A

Number of turns in primary coil $N_{P} = 200$

In case of transformer the relation between current and number of turns is given by,

$\frac{N_{S} }{N_{P} } = \frac{I_{P} }{I_{S} }$

For finding number of turns in secondary coil,

$N_{S} = \frac{I_{P} }{I_{S} } N_{P}$

$N_{S} = \frac{500}{25} \times 200$

$N_{S} = 4000$

Therefore, the number of turns in secondary coil is 4000

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2 years ago

A proton traveling to the right enters a region of uniform magnetic field that points into the page.When the proton enters this

neonofarm [45]

Answer:

(C) deflected toward the top of the page.(

Explanation:

We can answer this problem by using Fleming's Left Hand Rule. By doing so, we have to place:

- The index finger of the left hand in the direction of the magnetic field

- The middle finger of the left hand in the direction of the particle's velocity

- The thumb will give the direction of the force, and therefore the deflection of the proton

In this problem, we have:

- Magnetic field direction: into the page --> index finger

- Proton's velocity: to the right --> middle finger

By doing so, we observe that the thumb points towards the top of the page: therefore, the correct answer is

(C) deflected toward the top of the page.

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3 years ago

Find the velocity of a baseball thrown 78 m from third base to first base in 30 sec

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Answer:

V=2.6m/s

Explanation:

velocity=Distance/time

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2 years ago

An electron and a proton are fixed at a separation distance of 973 nm. Find the magnitude and the direction of the electric fiel

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Answer:

The magnitude is: $|E|=6084.1\: N/C$

The direction of E is in the negative x-direction.

Explanation:

The electric field equation is:

$E=k\frac{Q}{r^{2}}$

Where:

Q is the charge (we can choose the electron or the proton)
r is the distance (in our case is at the midpoint 973/2 nm)
k is the Coulomb constant ( $9*10^{9}\: Nm^{2}C^{-2}$ )

Using the electron charge ( $e = -1.6*10^{-19}\: C$ )

$E=-9*10^{9}\frac{1.6*10^{-19}}{(486.5*10^{-9})^{2}}$

The magnitude is:

$|E|=6084.1\: N/C$

The direction of E is in the negative x-direction.

I hope it helps you!

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2 years ago