A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
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Answer:
A. potential energy is 258720 Joule
Explanation:
A.Gravitational potential energy is: PE = m × g × h
velocity = 15.33 m/s when the car reaches the bottom of the hill.
where, m = mass
g = acceleration due to gravity
h = height from the bottom of hill.
The potential energy is : m×g×h
=(2200×9.8×12)
=258720 Joule
B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom
kinetic energy= (
)
where v = velocity
m= mass
therefore, v=
or, v=
or, v=15.33 m/s