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Juliette [100K]
3 years ago
9

LC Motor Sales conducted a survey to find out why people who bought cars at the dealership did not use it for ongoing service. T

he following responses were collected. What is the percent of respondents who felt LC Motors charged too much?
moved away = 42 responses
dislike the quality of service at LC Motors = 23 responses
service charges are too high at LC Motors = 102 responses
the service department is too crowded = 124 responses
the location is not convenient = 17 responses
other reasons = 26 responses

A. 8%
B. 7%
C. 37%
D. 31%
Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0

Answer: D

Step-by-step explanation:

42+23+102+124+17+26 = 334 total responses

LC Motors charged too much = 102

102/334 = .305..

Move the decimal 2 places to the right = 30.5

Rounds to 31%

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Answer:

I do not know

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I think so

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For a family with 3 children, what is the probability that they have exactly 2 boys and 1 girl?
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Answer:

\frac{3}{8}

Step-by-step explanation:

Possibilities (G for girls and B for boys):

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Read 2 more answers
if the angles of triangle RST and measure of angle R= (9x-2)degrees, and the measure of angle S=(4x+36) degrees, and measure of
Salsk061 [2.6K]

Answer:

R, T, S

Step-by-step explanation:

R+S+T=180 degrees

9x-2+4x+36+5x+20=180

18+54x=180

54x=162

x=3

R=9*3-2 (substitute x with 3)

R=25

S=4*3+36

S=48

T=5*3+20

T=35

Shortest to longest: R, T, S

8 0
3 years ago
(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

#SPJ4

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Rainbow [258]

Answer:

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Step-by-step explanation:

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