16) Na (s) + H2O(L) ---> H2 (g) + NaOH (aq)
17) O2 (g) + NH3 (g) --->H2O (L) + HNO3 (aq)
18) K (s) + Cl2 (g) ---> KCl (s)
19) Al (s) + HCl (aq) ---> H2 (g) + AlCl (aq)
20) Na3PO4 (aq) + CaCl2 (aq) ---> NaCl (s) + Ca3(PO4)2 (s)
Answer:
Explanation:
Most people when asked, “What is the equation of a line?”, will answer, “y = mx + b”. This is the
equation of a line in what is called slope-intercept form where “m” is the slope and “b” is the yintercept. So, how do you find the equation of a line? There are several different ways that you can find
the equation of a line. I find the equation of a line everytime by following the same three steps:
Step 1: Find the slope of the line.
Step 2: Use the slope to find the y-intercept.
Step 3: Use steps 1 and 2 to write the answer.
I will explain these steps by looking a several examples. Please understand that there are often several
different ways to complete each math problem, but I have found through the years that students are most
successful when the do problems the same way each and every time they attempt the problem. If you
know a different way to find the answer that is great, but I am going to show how to do the problem one
way and use the same technique everytime I see this problem.
The pH of the sodium hydroxide (NaOH) solution at the given concentration of 0.000519 M is determined as 10.72.
<h3>What is pH of solution?</h3>
The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration [H+] of the given solution.
Concentration of the basic solution, [OH⁻] = 0.000519
pOH = -log[OH⁻]
pOH = -log[0.000519]
pOH = 3.28
<h3>pH of the solution</h3>
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 3.28
pH = 10.72
Thus, the pH of the sodium hydroxide (NaOH) solution at the given concentration of 0.000519 M is determined as 10.72.
Learn more about pH here: brainly.com/question/26424076
What are you asking,
When?
Answer:
0.29mol/L or 0.29moldm⁻³
Explanation:
Given parameters:
Mass of MgSO₄ = 122g
Volume of solution = 3.5L
Molarity is simply the concentration of substances in a solution.
Molarity = number of moles/ Volume
>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.
Number of moles = mass/ molar mass
Molar mass of MgSO₄:
Atomic masses: Mg = 24g
S = 32g
O = 16g
Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol
= (24 + 32 + 64)g/mol
= 120g/mol
Number of moles = 122/120 = 1.02mol
>>>> From the given number of moles we can evaluate the Molarity using this equation:
Molarity = number of moles/ Volume
Molarity of MgSO₄ = 1.02mol/3.5L
= 0.29mol/L
IL = 1dm³
The Molarity of MgSO₄ = 0.29moldm⁻³