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Vsevolod [243]
3 years ago
10

B.) what fraction of a mole is 10g of clindamycin?

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
3 0
The molar mass of clindamycin, or C18H33ClN2O5S, is <span>424.98 grams. Divide how much you have by the amount per mole.

10 g / 424.98 (grams per mole) = .024 moles of clindamycin</span>
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Properties of carbon responsible for the pressence of millions of organic compound ​
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Answer:

Carbon has the ability to form very long chains of interconnecting C-C bonds. This property allows carbon to form the backbone of organic compounds, carbon-containing compounds, which are the basis of all known organic life. Nearly 10 million carbon-containing organic compounds are known.

5 0
3 years ago
1. How much energy (in KJ) is required to convert 50.0g of ice at – 30 ˚C to<br> steam at130˚C.
Vitek1552 [10]

Answer:

How much heat energy required to convert following?

How much heat energy, in kilojoules, is required to convert 47.0 g of ice at -18.0 C to water at 25.0 C ?

Specific Heat of Ice - 2.09 j/g * c

This is how I did it and the answer is wrong...Please check and correct me

Q = m * Cice * Change in Temp

Q = (47.0 g)(2.09 J/g*c)(43) = 4222.6 J * 0.001 kj / j = 4.22 kj

4 0
3 years ago
Forrest spills some acid on the lab floor. He notifies his teacher and begins to look for baking soda to neturalize the acid on
gregori [183]
His classmates should be notified next
7 0
3 years ago
Read 2 more answers
How many moles are 4.20 * 10 ^ 25 atoms of Ca?
aleksandr82 [10.1K]

Answer:

~69.744 moles of Ca

Explanation:

Using Avogadro's constant , we know that:

1 mole = 6.022 x 10^23 atoms

S0, the number of moles in 4.20 x 10^25 atoms of Ca:

=(4.20 x 10^25 x 1 )/(6.022 x 10^23)

~69.744 moles of Ca

Q2:How many atoms are in 0.35 moles of oxygen?

1 mole = 6.022 x 10^23 atoms

S0, the number of atoms in 0.35 moles of  oxygen:

=[0.35 x (6.022 x 10^23)]

=2.1077 x 10^23 atoms of Oxygen

Hope it helps:)

4 0
2 years ago
The amount of energy required to heat water for a 10-minute shower (50 gallons) is 2.2125 kJ. How many calories is this?
Zigmanuir [339]
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<span>
2.2125 kJ ( 239 calories / 1 kJ ) = 528.79 calories
</span><span>
</span>
6 0
3 years ago
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