Question

A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle containing 12.00 g of barium sulfate. What should be the final volume of the solution?
Find the numerical answer for this question and make sure to include the following:


What is the formula for molarity?

What is the molar mass for barium sulfate?

When you give your numerical answer, what are the correct significant figures and how do you know that is the correct amount?

Need this ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Answer: The volume of the solution is 85.7 mL

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}$ .....(1)

We are given:

Molarity of solution = 0.600 M

Given mass of $BaSO_4$ = 12.00 g

We know, molar mass of $BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol$

Putting values in equation 1, we get:

$0.600=\frac{12.00\times 1000}{233.4\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{12.00\times 1000}{233.4\times 0.600}=85.68mL=85.7mL$

The rule of significant number that is applied for the problems having multiplication and division:

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.

Hence, the volume of the solution is 85.7 mL