1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kkurt [141]
4 years ago
10

An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL,

0.60 atm, and 43°C, respectively. What was its initial volume?
Chemistry
1 answer:
svet-max [94.6K]4 years ago
4 0

Answer : The initial volume was, 71.2 mL

Explanation :

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

P_1=0.85atm\\V_1=?\\T_1=66^oC=[66+273]K=339K\\P_2=0.60atm\\V_2=94mL\\T_2=43^oC=[43+273]K=316K

Now put all the given values in above equation, we get:

\frac{0.85atm\times V_1}{339K}=\frac{0.60atm\times 94mL}{316K}

V_1=71.2mL

Therefore, the initial volume was, 71.2 mL

You might be interested in
True or False all non - metal elements are gassed at room temperature.​
saul85 [17]

Answer:

false

Explanation:

you have bromine , its a non metal and liquid in room temperature

7 0
3 years ago
Number of grams of hydrogen than can be prepared from 6.80g of aluminum​
Anastaziya [24]

Answer:

0.7561 g.

Explanation:

  • The hydrogen than can be prepared from Al according to the balanced equation:

<em>2Al + 6HCl → 2AlCl₃ + 3H₂,</em>

It is clear that 2.0 moles of Al react with 6.0 mole of HCl to produce 2.0 moles of AlCl₃ and 3.0 mole of H₂.

  • Firstly, we need to calculate the no. of moles of (6.8 g) of Al:

no. of moles of Al = mass/atomic mass = (6.8 g)/(26.98 g/mol) = 0.252 mol.

<em>Using cross multiplication:</em>

2.0 mol of Al produce → 3.0 mol of H₂, from stichiometry.

0.252 mol of Al need to react → ??? mol of H₂.

∴ the no. of moles of H₂ that can be prepared from 6.80 g of aluminum = (3.0 mol)(0.252 mol)/(2.0 mol) = 0.3781 mol.

  • Now, we can get the mass of H₂ that can be prepared from 6.80 g of aluminum:

mass of H₂ = (no. of moles)(molar mass) = (0.3781 mol)(2.0 g/mol) = 0.7561 g.

5 0
4 years ago
Many hospitals, and some doctors\' offices, use radioisotopes for diagnosis and treatment, or in palliative care (relief of symp
jekas [21]

<u>Answer:</u>

<u>For a:</u> The isotopic symbol of the above atom will be _{53}^{131}\textrm{I}

<u>For b:</u> The isotopic symbol of the above atom will be _{77}^{192}\textrm{Ir}

<u>For c:</u> the isotopic symbol of the above atom will be _{62}^{153}\textrm{Sm}

<u>Explanation:</u>

The isotopic representation of an atom is: _Z^A\textrm{X}

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

  • <u>For a:</u>  Iodine-131

Atomic number of iodine = 53

Mass number of iodine = 131

Symbol of iodine = I

The isotopic symbol of the above atom will be _{53}^{131}\textrm{I}

  • <u>For b:</u>  Iridium-192

Atomic number of iridium = 77

Mass number of iridium = 192

Symbol of iridium = Ir

The isotopic symbol of the above atom will be _{77}^{192}\textrm{Ir}

  • <u>For c:</u>  Samarium-153

Atomic number of samarium = 62

Mass number of samarium = 153

Symbol of samarium = Sm

The isotopic symbol of the above atom will be _{62}^{153}\textrm{Sm}

7 0
3 years ago
How would 0.073 be written in scientific notation
In-s [12.5K]

Answer:

7.3

⋅

10

−

2

Explanation:

8 0
3 years ago
Read 2 more answers
If 20. 3 grams of an aqueous solution of iron(ii) chloride, fecl2, contains 2. 71 grams of iron(ii) chloride, what is the percen
Hatshy [7]

If 20. 3 grams of an aqueous solution of iron(ii) chloride contains 2. 71 grams of iron(ii) chloride, then percentage by mass of  iron(ii) chloride in the solution is 13.34%

Calculation,

Given:

mass of an aqueous solution of iron(ii) chloride = 20. 3 grams

mass of iron(ii) chloride = 2. 71 grams

The percentage by Mass is equal to percentage of mass of solute present in total mass of solution. It is also known as Mass percentage.

percentage by Mass = 100× 2. 71 grams/20. 3 grams = 13.34%

Hence, the percentage by mass of  iron(ii) chloride in the solution is 13.34% .

to learn more about mass percentage

brainly.com/question/27108588

#SPJ4

7 0
2 years ago
Other questions:
  • Which statement tells an advantage for a single-celled organism?
    8·2 answers
  • The solubility of lead(ii) chloride is 0.45 g/100 ml of solution. what is the ksp of pbcl2? 4.9 × 10-2 1.7 × 10-5 8.5 × 10-6 4.2
    7·1 answer
  • Select the correct answer. When an atom in a reactant loses electrons, what happens to its oxidation number? A. Its oxidation nu
    5·2 answers
  • Which of the following is accurate when discussing specific heat?
    9·1 answer
  • Discuss how to separate a mixture of iron fillings, salt, sand, and wood chips.
    13·1 answer
  • Why do atoms move at different speeds depending on whether they are in liquids or solids.
    9·1 answer
  • I need literal help yall. if yall answer this you guys can get brainest
    10·1 answer
  • How many moles of Al are necessary to form 28.2 g of AlBr₃ from this reaction:
    12·1 answer
  • A change of state is a(n)<br> process.<br> A. irreversible <br> B. reversible
    10·2 answers
  • I need help finding both conjugate acid and base
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!