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Alexandra [31]
3 years ago
6

What type of power plant burns material to make electricity?

Physics
2 answers:
const2013 [10]3 years ago
8 0
<h2>Answer</h2>

Option D - Coal

<u>Explanation</u>

A fossil fuel power plant is a thermal power station in which fossil fuels are burned to produce electricity. Coal is a fossil fuel which is formed from the buried remains of plants and animals. Burning coal releases the energy that the plant absorbed from the sun. This energy is used to generate steam which is used to move a turbine to produce electricity. In this way, coal is burned by the power plants to produce electricity. In most of the countries, such plants provide most of the electrical energy used.

Alecsey [184]3 years ago
6 0
<h2>Hello!</h2>

The answer is: D. Coal

<h2>Why?</h2>

Coal power plants burn coal in to get steam, the steam flows into a turbine which is coupled to an electrical generator.

Coal power plants work burning high amounts of coal into a boiler, generation a lot of steam under extreme pressures. The steam is obtained when the water is heated by the burning coal, then the steam is cooled, being transformed in liquid water again (due the condensation process) and it's sent back on a cyclical process.

Have a nice day!

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Unpolarized light passes through a combination of two ideal polarizers. The transmission axes of the first polarizer and the sec
Yuliya22 [10]

Answer:

62.5 %

Explanation:

Let the initial intensity of unpolarized light is Io.

After first polariser the intensity of light becomes I'.

So, I' = \frac{I_{0}}{2}

Now it passes through another polariser. The angle between the first polariser and the second polariser is given by Ф. The intensity is I''.

According to the law of Malus

I'' = I' Cos^{2}\phi

Here, Ф = 30 degree

I'' = \frac{I_{0}}{2} Cos^{2}30=0.375I_{0}

The percentage change in the intensity is given by

\frac{I_{0}-I''}{I_{0}}\times 100=\frac{I_{0}-0.375I_{0}}{I_{0}}\times100

= 62.5 %

7 0
3 years ago
What is one function of a transistor?
const2013 [10]

Answer:

amplifying signals is the correct answer

Explanation:

8 0
2 years ago
A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 47 N. How f
Novosadov [1.4K]

Answer:

7.53 m

Explanation:

Force, F = 47 N

initial velocity, u = 0

Final kinetic energy, Kf = 354 J

Let the distance traveled by the student is s.

According to the work energy theorem,

Work done by all forces = Change in kinetic energy

Force x distance = final kinetic energy - initial kinetic energy

F x s = kf - ki

47 x s = 354

s = 7.53 m

4 0
3 years ago
julia throws a ball vertically upward from the ground with a speed of 5.89m/s. Andrew catches it when it is on its way down at a
aliya0001 [1]
Vo = 5.89 m/s Y = 1.27 m g = 9.81 m/s^2 
Time to height 
Tr = Vo / g Tr = (5.89 m/s) / (9.81 m/s^2) Tr = 0.60 s 
Max height achieved is:
H = Vo^2 / [2g] H = (5.89 )^2 / [ 2 * (9.81) ] H = (34.69) / [19.62] H = 1.77 m 
It falls that distance, minus Andrew's catch distance:
h = H - Y h = (1.77 m) - (1.27 m) h = 0.5 m 
Time to descend is therefore:
Tf = √ { [2h] / g ] Tf = √ { [ 2 * (0.5 m) ] / (9.81 m/s^2) } Tf = √ { [ 1.0 m ] / (9.81 m/s^2) } Tf = √ { 0.102 s^2 } Tf = 0.32 s 
Total time is rise plus fall therefore:
Tt = Tr + Tf Tt = (0.60 s) + (0.32 s) Tt = 0.92 s           (ANSWER)
8 0
3 years ago
The specific heat of gold is 0.126 J/g°C. What mass of gold would change its temperature from 25.0 °C to 60.0 °C with the additi
fiasKO [112]
<span>The amount of heat energy needed to increase the temperature of a substance by </span>\Delta T<span> is given by:
</span>Q=m C_s \Delta T<span>
where m is the mass of the substance, Cs is its specific heat capacity and </span>\Delta T<span> is the increase in temperature of the substance.

In this problem, we have a certain mass m of gold, with specific heat capacity </span>C_s=0.126 J/g^{\circ}C<span>, to which we add Q=2825 J of energy. Its temperature increases by </span>\Delta T=60-25=35 ^{\circ}C<span>. Therefore, if we re-arrange the previous equation, we can find the mass of the block of gold:
</span>m= \frac{Q}{C_s \Delta T} = \frac{2825J}{0.126\cdot 35}} =641 g<span>
So, the correct answer is B.</span>
3 0
3 years ago
Read 2 more answers
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