A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 47 N. How f
ar must the student be pushed, starting from rest, so that her final kinetic energy is 354 J ?
1 answer:
Answer:
7.53 m
Explanation:
Force, F = 47 N
initial velocity, u = 0
Final kinetic energy, Kf = 354 J
Let the distance traveled by the student is s.
According to the work energy theorem,
Work done by all forces = Change in kinetic energy
Force x distance = final kinetic energy - initial kinetic energy
F x s = kf - ki
47 x s = 354
s = 7.53 m
You might be interested in
Answer:
-.457 m/s^2
Explanation:
Actual weight = 60 .3 (9.81) = 591.54 N
Accel of lift changes this to 60.3 ( 9.81 - L) where L - accel of lift
60.3 ( 9.81 - L ) = 564
solve for L = .457 m/s^2 DOWNWARD
so L = - .457 m/s^2
Answer:
least distance= 13mm
ratio of the lattice = 1 : 0.71 : 0.58
Explanation:
given λ₁ = 650nm = 650×10⁻⁹m, λ₂ = 500nm = 500×10⁻⁹m
Jack Kilby invented the circuit
Answer:
d = 3.8857 g/cm^3
Explain:
Formula/: d = m/V
Hope this helps!
(a brainliest would be appreciated)
Answer:
because it is an ice that is why it melt
