Answer:
Energy of one mole of photon will be 
Explanation:
We have given wavelength of photon 
Velocity of light is given 
Plank's constant 
Energy of the photon is given by 
We have to find the energy of one mole of photon
One mole of photon is equal to 
So energy of one mole of photon will be equal to 
So energy of one mole of photon will be
The astrometric technique of planet detection works best for massive planets around nearby stars.
Answer:
33.14 m/s
Explanation:
The mass of the block is 121g or .121 kg. As the bullet is lodged in the block the total mass is 121+14 = 135 g or 0.135 kg.
The frictional force that makes the block come to a stop is normal force* coefficient of friction = 0.135 * 9.8 * 0.7 = 0.9261 N
As the block comes to rest after sliding for 8.3 meters the energy it was given by the bullet is
0.135 * 9.8 * 0.7 * 8.3
= 7.69 Nm
Now this energy is provided the bullet. So the energy in the bullet was equal to
1/2 * mv² = 0.5 * 14 * v².
0.5 * 0.014 * v^2 = 0.135 * 9.8 * 0.7 * 8.3 = 7.69
=> 0.007 * v² = 7.69
=> v² = 7.69 / 0.007
=> v² = 1098.57
=> v = √1098.57
=> v = 33.14 m/s
