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3 years ago

Calculate the displacement of a car waxing point of 11 m to the final positions of 4 meters

Physics

1 answer:

Nastasia [14]3 years ago

3 0

Answer:

-7 m

Explanation:

Displacement is a vector connecting the initial position of motion of an object to its final position.

For the car in this problem, we have:

- Initial position: + 11 m

- Final position: + 4 m

Therefore, the vector displacement will be:

d = +4 - (+11) = -7 m

Which means:

- Magnitude of 7 m

- Negative direction

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Answer:

$\theta = 49.56 degree$

Explanation:

Relative horizontal velocity of plane with respect to the car is given as

$v_r = v_p - v_c$

so we have

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$v_c = 155 km/h$

now we have

$v_r = 215 - 155$

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$78 = \frac{1}{2}(9.81)t^2$

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so the distance of the car must be

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2 years ago

Tendons are strong elastic fibers that attach muscles to bones. To a reasonable approximation, they obey Hooke's law. In laborat

meriva

Answer:

k = 200 N/m

Explanation:

given,

mass of the object = 251 g

= 251 x 10⁻³ Kg = 0.251 Kg

distance of tendon stretch = x = 1.23 cm

= 1.23 x 10⁻² = 0.0123 m

using the formula

F = k x

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Answer:

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Rate of interest (R) = 4.5 %

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