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just olya [345]
4 years ago
5

Calculate the displacement of a car waxing point of 11 m to the final positions of 4 meters

Physics
1 answer:
Nastasia [14]4 years ago
3 0

Answer:

-7 m

Explanation:

Displacement is a vector connecting the initial position of motion of an object to its final position.

For the car in this problem, we have:

- Initial position: + 11 m

- Final position: + 4 m

Therefore, the vector displacement will be:

d = +4 - (+11) = -7 m

Which means:

- Magnitude of 7 m

- Negative direction

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Answer:

Another danger that comes with intrapreneurs is the lack of patience from other people in the office. To people who have worked their whole lives in one company, they might expect to see instant results from somebody who has waltzed in and promised big things.

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3 years ago
_______ are nonmetals that react with metals to form salts.
kari74 [83]

i’m pretty sure it’s , the alkali metals


5 0
3 years ago
A quarterback takes the ball from the line of scrimmage, runs backward for 12.1 yds, then runs sideways parallel to the line of
Over [174]

Answer:

The answer is 35.45 yds

Explanation:

You have to picture this to be able to understand it better (see attachment).

Start at the origin which is when the quarterback (QB) takes the ball. He runs backwards 12.1 yards, runs sideways for 19.8 yards (it doesn´t matter if he runs right or left), then he throws the ball forward 41.5 yards. If you look at the attachment, you can see I drew the path that the football followed. And then connected the dots from the origin and finish. The distance between those two points is the magnitude of the resultant displacement.

In order to calculate it, all you need to do is use the Pythagoream theorem, which says that the square of the hypotenuse equals the sum of the squares of the legs a and b of the triangle rectangle.

  1. R^{2} = a^{2} + b^{2} then solve for R
  2. R = \sqrt{a^{2}+b^{2}  }

In this case, you know the length of leg a to be 19.8 yards which how much it moves sideways. And then, to get the length of leg b, all you need to do is substract how much it moved backwards from the 41.5yards forward displacement. This results in b leg being 29.4 yards long.

Now you have a triangle with:

  • a = 19.8 yards
  • b = 29.4 yards

Substituting this numbers in the equation:

  • R = \sqrt{19.8^{2}+29.4^{2}  }
  • R = 35.45 yards

3 0
3 years ago
Four uniform spheres, with masses mA = 200 kg, mB = 250 kg, mC = 1700 kg, and mD = 100 kg, have (x, y) coordinates of (0, 50 cm)
rusak2 [61]

Answer:

F_2=2.43\times10^{-19}\ N

\theta=21.496^{\circ} in the anticlockwise direction from the positive x- axis.

Explanation:

Given are the masses of various spheres with their names in subscript:

  • m_A=200\ kg
  • m_B=250\ kg
  • m_C=1700\ kg
  • m_D=100\ kg

Now their respective coordinate positions (in cm) are as given below:

  • P_A=(0,50)
  • P_B=(0,0)
  • P_C=(-80,0)
  • P_D=(40,0)

<u>Now force on B due to A:</u>

F_{BA}=G\times \frac{200\times 250}{50^2}

F_{BA}=20G\ N

<u>Now force on B due to C:</u>

F_{BC}=G\times \frac{1700\times 250}{80^2}

F_{BC}=66.406G\ N

<u>Now force on B due to D:</u>

F_{BD}=G\times \frac{100\times 250}{40^2}

F_{BD}=15.625G\ N

<em>We observe that the forces due to masses  C&D act opposite in direction.</em>

<u>So, the net force in the x-direction:</u>

F_x=F_{BC}-F_{BD}

F_x=66.406G-15.625G

F_x=50.781G\ N in the positive x-direction

<em>We have only one force in y-direction due to mass A.</em>

So,

F_y=20G\ N in the positive y-direction.

<u>Now the net force:</u>

F_2=\sqrt{F_y^2+F_x^2}

F_2=\sqrt{(20G)^2+(50.781G)^2}

F_2=54.5776G^2\ N

F_2=2.43\times10^{-19}\ N

<u>Now the direction of this force with respect to x-axis:</u>

tan\ \theta=\frac{F_y}{F_x}

tan\ \theta=\frac{20G}{50.781G}

\theta=21.496^{\circ} in the anticlockwise direction from the positive x- axis.

3 0
3 years ago
Read 2 more answers
What is the wavelength of an X-ray photon with energy 8.0 keV (8000 eV)? (1 eV = 1.60 × 10−19 joule.)
katrin2010 [14]

Answer:

Wavelength = 0.15 nm

Frequency = 1939.3939\times 10^{15}Hz

Explanation:

We have given photon energy E = 8 KeV = 8000 eV

In question it is given that 1eV=1.6\times 10^{-19}J

So 8000eV=1.6\times 8000\times 10^{-19}=12800\times 10^{-19}j

Plank's constant h=6.6\times 10^{-34}js

We know that photon energy is given by E=h\nu

So 12800\times 10^{-19}=6.6\times 10^{-34}\nu

\nu =1939.3939\times 10^{15}Hz

Now wavelength \lambda =\frac{c}{f}=\frac{3\times 10^8}{1939.3939\times 10^{15}}=0.0015\times 10^{-7}m=0.15nm

3 0
4 years ago
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