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Ksju [112]
2 years ago
6

If the voltage drop across the first resistor is 13.00V, then how many volts remain for the 2nd resistor?

Physics
2 answers:
Scorpion4ik [409]2 years ago
8 0

Answer:

2+1

Explanation:

2+1

shutvik [7]2 years ago
5 0
I think it is
2+1
But not sure
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Displacement is the difference between the initial position and the____ position of an object
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<span>Displacement is the difference between the initial position and the FINAL position of an object.

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3 years ago
What is the velocity in meters per second of a runner who runs exactly 110 m toward the beah in 72 seconds?
rjkz [21]
B) 1.53 m/s towards the beach
8 0
3 years ago
Read 2 more answers
Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where l
goblinko [34]

Answer:

Δt = 5.29 x 10⁻⁴ s = 0.529 ms

Explanation:

The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.

\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}

where,

Δt = required time interval = ?

Δs = distance between ears = 18 cm = 0.18 m

v = speed of sound = 340 m/s

Therefore,

\Delta t = \frac{0.18\ m}{340\ m/s}

<u>Δt = 5.29 x 10⁻⁴ s = 0.529 ms</u>

4 0
3 years ago
Mary walked north from her home to Sheila's home, which is 4.0 kilometers away. Then she turned right and walked another 3.0 kil
bixtya [17]
The answer is speed: 4.7 km/h, velocity: 3.3 km/h.

Distances and time are given:
d1 =  4 km
d2 = 3 km
d3 = 5 km
t = 1.5 h

The speed can be expressed as a distance (d) divided by time (t). The average speed (s) is total distance travelled divided by time:
s = (d1 + d2)/t = (4+3)/1.5 = 7/1.5 = 4.7 km/h

The average velocity (v) is total displacement (d₁) from the starting point divided by time. Since Mary's starting point was home, and she walked to the supermarket, which is 5.0 kilometers from her own home, her displacement is 5 km:
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8 0
3 years ago
2 * 1.5 * (.850/2)^2A small ball with mass 1.50 kg is mounted on one end of a rod 0.850 m long and of negligible mass. The syste
grin007 [14]

Answer

given,

mass of the rod = 1.50 Kg

length of rod = 0.85 m

rotational velocity = 5060 rev/min

now calculating the rotational inertia of the system.

I = m L^2        

where L is the length of road, we will take whole length of rod because mass is at  the end of it.      

I = 1.5 \times 0.85^2  

I = 1.084 kg.m²                        

hence, the rotational inertia the system is equal to I = 1.084 kg.m²

8 0
2 years ago
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