In a circle or circular motion
Answer:
44.4cm
Explanation:
glass has an index of refraction .n = 1.54
radii of curvature of 40 cm R1 = 40 by
radii of curvature of 600 cm R2 = 60
Now, by lens maker formula
1/f = (n - 1) (1/R1 - 1/R2)
Putting in the given values for n = 1.54 , we get f = 22.2


f = 1 / 0.0225
f = 44.4cm
so, focal length in air will be = 44.4 cm
Answer:
t = 0.67 [s]
Explanation:
To solve this problem we must use the following kinematics equation.

Vf = final velocity = 20[m/s]
Vi = initial velocity = 10 [m/s]
a = aceleration = 15 [m/s^2]
Now replacing in the equation we have:
20 = 10 + (15*t)
t = (20-10)/15
t = 0.67 [s]
The particles that move in orbits of the same radius have the same momentum.
<h3>
Orbital angular momentum:</h3>
A point particle's three-dimensional angular momentum is traditionally represented by the pseudovector r p, which is the cross product of the particle's position vector r (relative to some origin) and momentum vector, which in Newtonian physics is denoted by p = mv.
L = mr
= mr²w is the particle's orbital angular momentum in units of magnitude. The part of the particle's velocity that is here perpendicular to the axis of rotation is designated as
The right-hand rule indicates the direction of the angular momentum. In isolated systems, the angular momentum is conserved.
Learn more about momentum here:
brainly.com/question/25849204
#SPJ4
Answer:
F = 534.6[N]
Explanation:
We must find the pressure exerted by the water at the depth of the boat, by means of the following equation.

where:
Ro = density of sea water = 1027 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = wáter Depth = 6.25 [m]
Now replacing:
![P=1027*9.81*6.25\\P=62967.93[Pa]](https://tex.z-dn.net/?f=P%3D1027%2A9.81%2A6.25%5C%5CP%3D62967.93%5BPa%5D)
The net force is:
![F = P*A\\F = 62967.93*0.00849\\F = 534.6[N]](https://tex.z-dn.net/?f=F%20%3D%20P%2AA%5C%5CF%20%3D%2062967.93%2A0.00849%5C%5CF%20%3D%20534.6%5BN%5D)