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Andrew [12]
4 years ago
6

Dana has a sports medal suspended by a long ribbon from her rearview mirror. As she accelerates onto the highway, she notices th

at the medal is hanging at an angle of 13 ∘∘ from the vertical.What is her acceleration?
Physics
1 answer:
ivann1987 [24]4 years ago
7 0

Answer:

2.26m/s^2

Explanation:

Suppose the tension in the ribbon is T.

The upwards component of the tension = Tcos13

The horizontal component of the tension = Tsin13

The weight of the medal = mg

In a vertical direction, mg is balanced by Tcos13, so mg=Tcos13, so T  = mg/cos13. The horizontal component of T is the force causing m to accelerate.  

F = ma\\T\sin13^{\circ} = ma

Substituting T= mg/cos13 gives:

\frac{mg}{cos13^{\circ}}sin13^{\circ} = ma

m cancels and you have

g\tan13 = a\\a=9.81\tan13^{\circ} \approx 2.26m/s^2

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Explanation:

From the 1st Law of linear motion which states that when a body goes into motion, it will continue doing so until it is stopped by force. So the body of the rider keeps moving until it is been stopped and the stopping could be as a result of an impact of any part of the body which includes the head it an object. Also the 3rd Law of Motion will also be applicable because for every action, there will be equal and opposite reaction. The magnitude of the impact will be as a result of the force with which the crash took place as well.

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