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3 years ago

Waves crash on a beach one after another. Why doesn't water pile up on the beach

Chemistry

2 answers:

Klio2033 [76]3 years ago

6 0

sand

Explanation:

it is absorbing it

UNO [17]3 years ago

3 0

Answer:

Sand absorbers the water

Explanation:

On other days, however, when winds blow surface water toward land, the water can't just pile up on the beach, so water near the bottom has to compensate, moving offshore. ... One measures the speed and direction of flowing water by reflecting sound off particles carried by the currents.

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When 2.3 × 10^3 g of CaCO3 are heated, the actual yield of CaO is 1.09 × 10^3g. What is

iren [92.7K]

The percent yield : 4. 84.58%

<h3>Further explanation</h3>

Reaction

CaCO₃ ⇄ CaO+CO₂

mass CaCO₃ = 2.3 × 10³ g

mol CaCO₃ (MW=100.0869 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{2.3\times 10^3}{100,0869}\\\\mol=22.98$

From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98

mass CaO(MW=56.0774 g/mol)⇒ (theoretical) :

$\tt mass=mol\times MW\\\\mass=22.98\times 56,0774\\\\mass=1288.659~g$

The percent yield :

$\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{1090}{1288.659}\times 100\%\\\\\5yield=84.58\%$

5 0

3 years ago

Based on my scale, I have 35g of aluminum. How many aluminum atoms is this? SHOW YOUR WORK.

Aleksandr-060686 [28]

One mole of a substance contains 6.02×10∧23 particles,
1 mole of a aluminium contains 27 g
35 g of aluminium contains 35/27 =1.296 moles
Thus, the number of particles will be 1.296 × 6.02 ×10∧23
= 7.804 × 10∧23 particles,
Hence, 35 g of Aluminium contains 7.804 × 10∧23 atoms

3 0

3 years ago

Lithium (Li): 1s 2sB<br> A=<br> B=

topjm [15]

Answer:

A = 2

B = 1

Explanation:

The atomic number of lithium is 3.

Its atomic mass is 7 amu.

It is present in group group 1.

It has one valance electron.

Lithium is alkali metal it form salts.

It is silvery soft metal. It has lowest density as compared to all other metals.

It react vigorously with water.

It is used in rechargeable batteries which are used in camera, mobile, laptops etc.

The electronic configuration of Li:

Li₃ = 1s² 2s¹

Thus,

A = 2

B = 1

8 0

2 years ago

At a certain concentration of H2 and NH3, the initial rate of reaction is 0.120 M / s. What would the initial rate of the reacti

mel-nik [20]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

$rate=k[H_2]^2[NH_3]$

At a certain concentration of $H_2 and [tex]I_2, the initial rate of reaction is 0.120 M/s. What would the initial rate of the reaction be if the concentration of [tex]H_2 were halved.Answer : The initial rate of the reaction will be, 0.03 M/sExplanation :Rate law expression for the reaction:[tex]rate=k[H_2]^2[NH_3]$

As we are given that:

Initial rate = 0.120 M/s

Expression for rate law for first observation:

$0.120=k[H_2]^2[NH_3]$ ....(1)

Expression for rate law for second observation:

$R=k(\frac{[H_2]}{2})^2[NH_3]$ ....(2)

Dividing 2 by 1, we get:

$\frac{R}{0.120}=\frac{k(\frac{[H_2]}{2})^2[NH_3]}{k[H_2]^2[NH_3]}$

$\frac{R}{0.120}=\frac{1}{4}$

$R=0.03M/s$

Therefore, the initial rate of the reaction will be, 0.03 M/s

5 0

3 years ago

Can someone please help me with this asap, it’s due today please help me

hammer [34]

Answer:

lol I hate chemical but let me give some advice

Explanation:

Please go on Khan Academy or look at your notes and I promise you can figure out! Seriously, I am trying to be helpful not like the annoying teacher that says "figure it out"

7 0

3 years ago