Answer:
It does not change and object's mass
Boyle’s Law P1V1 = P2V2
P1 = 0.80 atm V1 = 1.8 L
P2 = 1.0 atm V2 = ??
(.8 atm)(1.8 L) = (1.0 atm)(V2)
1.44 atm x L = 1 atm V2
(a) sodium phosphate > sulfuric acid > phosphoric acid > sucrose (sugar)
<span>(b) sucrose (sugar) > sulfuric acid > phosphoric acid > sodium phosphate </span>
<span><u>(c) sulfuric acid > sodium phosphate > phosphoric acid > sucrose (sugar) </u></span>
<span>(d) sodium phosphate > phosphoric acid > sulfuric acid > sucrose (sugar)</span>
Answer:
The correct answer is 190.5 mL of 1.00 M KH₂PO₄
Explanation:
A phosphate buffer is composed by phosphate acid (KH₂PO₄) and its conjugated base (K₂HPO₄). To obtain the relation between the concentrations of base and acid to add, we use Henderson-Hasselbach equation:
pH= pKa + log 
We have: pH= 6.97 and pKa= 7.21. So, we replace the values in the equation:
6.97= 7.21 + log 
6.97-7.21= log 
-0.24= log 
= 
0.575 = 
= 
It means that you have to mix a volume 0.575 times of conjugated base and 1 volume of acid. If we assume a total buffer concentration of 1 M, we have:
base + acid = 1
base= 1 - acid
We replace in the previous equation:
0.575= 
0.575 acid= 1 - acid
0.575 acid + 1 acid= 1
1.575 acid = 1
acid= 1/1,575
acid= 0.635
base= 1 - acid = 1 - 0.635 = 0.365
For a total volume of 300 ml, the volumes of both acid and base will be:
300 ml x 0.635 M = 190.5 ml of acid (KH₂PO₄)
300 ml x 0.365 M= 109.5 ml of base (K₂HPO₄)
We can corroborate our calculations as follows:
190.5 ml + 109.5 ml = 300 ml
109.5 ml / 190.5 ml = 0.575