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PtichkaEL [24]
2 years ago
10

Gaseous nitrogen dioxide dissolved in warm liquid water to form hno3 and gaseous nitrogen monoxide enter a balanced equation for

this reaction
Chemistry
1 answer:
Andre45 [30]2 years ago
6 0

Answer:

3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)

Explanation:

Gaseous nitrogen dioxide = NO₂ (g)

Liquid water = H₂O (l)

Because the reactants are dissolved = HNO₃ (aq)

Gaseous nitrogen monoxide = NO (g)

In order for a reaction to be balanced, there needs to be an equal amount of each type of atom on both sides of the equation. The equation can be balanced by adding coefficients to modify the quantities of certain compounds.

The unbalanced equation:

NO₂ (g) + H₂O (l) ---> HNO₃ (aq) + NO (g)

<u>Reactants</u>: 1 nitrogen, 3 oxygen, 2 hydrogen

<u>Products</u>: 2 nitrogen, 4 oxygen, 1 hydrogen

The balanced equation:

3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)

<u>Reactants</u>: 3 nitrogen, 7 oxygen, 2 hydrogen

<u>Products</u>: 3 nitrogen, 7 oxygen, 2 hydrogen

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3 years ago
Dr. I. M. A. Brightguy adds 0.1727 g of an unknown gas to a 125-mL flask. If Dr. B finds the pressure to be 736 torr at 20.0°C,
AlladinOne [14]

Answer:

The gas that Dr. Brightguy added was O₂

Explanation:

Ideal Gases Law to solve this:

P . V = n . R . T

Firstly, let's convert 736 Torr in atm

736 Torr is atmospheric pressure = 1 atm

20°C = 273 + 20 = 293 T°K

125 mL = 0.125L

0.125 L . 1 atm = n . 0.082 L.atm / mol.K . 293K

(0.125L .1atm) / (0.082 mol.K /L.atm . 293K) = n

5.20x10⁻³ mol = n

mass / mol = molar mass

0.1727 g / 5.20x10⁻³ mol = 33.2 g/m

This molar mass corresponds nearly to O₂

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3 years ago
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What best describes how the behavior of rocks changes when they become deeply buried and placed under high levels of heat and pr
Debora [2.8K]

Answer:

They become ductile and deform plastically

Explanation:

When rocks are buried by the materials up to a greater depth, then the confining pressure increases significantly. This results in the ductile behavior of the rocks at such depth. These rocks are present in the ductile region where the depth is about more than 20 to 30 km. Here the rocks are subjected to extremely high pressure and temperature conditions, which favors the transformation of rocks into more higher-grade metamorphic rocks. It is also enhanced due to the geothermal gradient.

Under such high pressure and temperature, the rocks show the behavior of plasticity, where the rocks undergo bending, buckling as well as they tend to flow, and there occurs low strain rate, resulting in the permanent deformation of rocks.

Thus, the rocks become ductile and deform plastically at such conditions.

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4 years ago
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