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3 years ago

Write a quadratic equation with integer coefficients having the given numbers as solutions.

Mathematics

1 answer:

slava [35]3 years ago

7 0

9514 1404 393

Answer:

x² -22 = 0

Step-by-step explanation:

The roots are opposites, so the equation is pretty simple.

x = ±√22

x² = 22 . . . . . square both sides

x² -22 = 0 . . . . your quadratic equation in standard form

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Anybody help please hm

77julia77 [94]

Answer:

Step-by-step explanation:

if you use a calculator, it will come up as 1. I don't know why, but it does.

Hope this helps!

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1 year ago

if zakyrah has 5 songs and dymin has 2 songs on itunes.if zakyrah has 150 song how many does dymin have

Marianna [84]

60
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2 years ago

A dozen more than a number minus twice the number

scZoUnD [109]

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2 years ago

Read 2 more answers

For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

4 0

3 years ago

If f(x)= 1/3x and g(x)=3x, then what are g * f (x) and g*f(1/2)

MrMuchimi

The correct answer is: 3) " x ; 1/2" .
_____________________________________________________
Explanation:
_____________________________________________________
Question 1)

g [ f(x) ] = ? ;

→ Given: " f(x) = 1/3 x " ;

→ Given: " g(x) = 3x " ;
__________________________________
g [ f(x) ] = g(1/3 x) = 3(1/3 x) = 1x = "x" .
__________________________________
Question 2)

g [ f(1/2) ] = ? ;
__________________________________
→ Given: " f(x) = 1/3 x " ;

→ f(1/2) = (1/3) * (1/2) = (1*1) / (3*2) = (1/6) ;

→ g [ f(x) ] =

g(1/6) = 3* (1/6) = (3/1) * (1/6) = (3*1) / (1*6) = 3/6 = (3÷3) / (6÷3) = " 1/2 " .
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3 0

3 years ago