You need to use q = mc(delta t)
<span>Solve for c: </span>
<span>c = q / m(delta t) </span>
<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>
<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
4 elements are classified in group 4 like titanium, zirconium, hafnium and ruthorfordium
A. Each is found outside the nucleus
The required temperature of the sample of gas is 823K.
<h3>What is ideal gas equation?</h3>
Ideal gas equation gives idea about the behavior of gas at different condition & represented as:
PV = nRT, where
- P = pressure = 500 torr = 0.657 atm
- V = volume = 5.01 L
- R = universal gas constant = 0.082 L.atm / K.mol
- T = temperature = ?
- n = moles
Moles will be calculated as:
n = W/M, where
- W = given mass
- M = molar mass
Moles of Neon gas = 1g / 20.1g/mol = 0.049 mole
On putting all these values in the above equation, we get
T = (0.657)(5.01) / (0.049)(0.082) = 822.8 = 823 K
Hence required temperature of the sample is 823 K.
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Meteorologist study weather.so i would say the answer is meteorologist.