Please Help!! I WILL MARK BRAINLIEST IF CORRECT!! What type of reaction is shown below?
1 answer:
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Answer:
Compound x =
Explanation:
Let the compound be x
Assuming we have a 100g of compound x
<u>Given the following data;</u>
Magnesium, Mg = 21.6% = 21.6g
Carbon, C = 21.4% = 21.4g
Oxygen, O = 57.0% = 57.0g
Now, we would find the amount of moles for each element.
Atomic mass of Mg = 24.30g
Atomic mass of C = 12.01g
Atomic mass of O = 16.00g
<u>Amount of moles for Mg;</u>
21.6*(1/24.30) = 0.89mol
<u>Amount of moles for C;</u>
21.4*(1/12.01) = 1.78mol
<u>Amount of moles for O;</u>
57.0*(1/16.00) = 3.56mol
We then divide by the smallest to find the ratio;
0.89/0.89 = 1 Mol of Mg
1.78/0.89 = 2 Mol of C
3.56/0.89 = 4 Mol of O
Therefore, the ratio of Mg, C and O is 1:2:4.
Compound x =
Hence, the empirical formula of the compound is
Answer:
The answer to the question is
The change in the kinetic energy of the object is 600 J
Explanation:
The known variables are,
Mass of object, m = 100 kg
Force of object, F = 100 N
The relation for kinetic energy = KE = = 0.5·m·v²
Therefore to find v we first find the acceleration from
F = m·a =10.0 kg × a = 100 N,
Where a = acceleration of the object =100/10 = 10 m/s²
To find the velocity, v, we use the relationship
v² = u² + 2 × a × S, where S is the distance of motion = 6.00 m and u is the initial velocity, u = 0 m/s, therefore
v² = 0 + 2 × 10 m/s² × 6 m = 120 m²/s² or v = 10.95 m/s
Therefore KE = 0.5 × 10 kg × (10.95 m/s)² = 600 J
where the initial velocity, u = 0 m/s
Initial kinetic energy of the object = KE₁ = 0.5 × 10 × 0² = 0
The change in kinetic energy of the object = 600 J - 0 J = 600 J