Identify the strongest attractive forces between the particles of each of the following A.CH3OH B.CO C.CF4 D.CH3-CH3
2 answers:
Answer: A) hydrogen bonding, B) dipole-dipole forces, C) London dispersion forces and D) London dispersion forces.
Explanation: Methanol is a polar covalent molecule means it has dipole-dipole forces of attraction. Since, hydrogen is bonded to more electron negative oxygen atom, this molecule has hydrogen bonding. So, strongest attractive forces for this molecule are hydrogen bonding.
CO is a polar covalent molecule and so it has dipole-dipole forces of attraction.
has four polar covalent bonds but the over all molecule is nonpolar as the dipole moment of one C-F bond is canceled by its opposite C-F bond as the molecule is tetrahedral. Being nonpolar, the molecule has london dispersion forces only.
Ethane is also a nonpolar molecule and so it has london dispersion forces.
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Answer:
Explanation:
Chlorine has electronic configuration of 2 , 8 , 7
In n = 3 there are 7 electrons out of which 2 are in s , and 5 are in p . But out of 5 electrons in p , one electron jumps into d orbital . so the electronic configuration becomes as follows
= 7
These orbitals like sp³d hybridise to form 7 degenerate orbitals out of which 2 orbitals contain electrons in pairs and rest three are singly occupied by electrons.( unpaired electrons )