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4 years ago

In what way did Galileo prove Aristotle

1 answer:

8 0

According to the story, Galileo discovered through this experiment that the objects fell with the same acceleration, proving his prediction true, while at the same time disproving Aristotle's theory of gravity (which states that objects fall at speed proportional to their mass).

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Classify the following dienes and polyenes as isolated, conjugated, cumulated, or some combination of these classifications.

lawyer [7]

Answer:

cycloocta-1,4-diene- isolated double bond

cycloocta-1,3-diene- conjugated double bond

cyclodeca-1,2-diene- cumulated double bond

cycloocta-1,3,5,7-tetraene- conjugated double bond

cyclohexa-1,3,5-triene (benzene) - conjugated double bond

penta-1,2,4-triene- cumulated and conjugated double bond

Explanation:

A conjugated double bond is a system that contains alternate double and single bonds. It is renowned for its unusual stability.

A cumulated double bond is a double bond system involving about three atoms e.g C=C=C.

An isolated double bond is a system of double bonds separated by more than one single bond.

8 0

4 years ago

A. What causes these H-bonds to form? (Hint: Look at the charged regions.)

Shkiper50 [21]

Answer:

Hydrogen bonding is caused by the tendency of some atoms in molecules to attract electrons more than their accompanying atom. This gives the molecule a permanent dipole moment , it makes it polar, so it acts like a magnet and attracts the opposite end of other polar molecules.

Explanation:

3 0

3 years ago

The atomic number of nitrogen is 7. The mass is 14.01. This means that a) All nitrogen atoms have exactly 7 neutrons b) A small

adelina 88 [10]

This means that there are 7 protons in the nucleus of a nitrogen atom.

5 0

3 years ago

Read 2 more answers

The following name is wrong. Draw the structure based on it and correct the name: 1,1,1âˆ’trimethylheptane

Nana76 [90]

2,2-Dimethyloctane is the correct name.

Eight C atoms make up the longest continuous carbon chain, hence the term "octane" for this molecule.

<h3>Description of the chemical structure</h3>

There are 31 bonds in the 2,2-Dimethyloctane molecule overall (s) There are 5 rotatable bonds and 9 non-H bonds (s).
Skeletal formula, which is the accepted notation for organic compounds, is another name for the 2D chemical structure illustration of 2,2-Dimethyloctane.
Skeletal formula, which is the accepted notation for organic compounds, is another name for the 2D chemical structure illustration of 2,2-Dimethyloctane.
In the 2,2-Dimethyloctane chemical structure, the carbon atoms are implied to be at the corner(s) and hydrogen atoms coupled to carbon atoms are not mentioned; instead, it is assumed that each carbon atom is connected to enough hydrogen atoms to form four bonds.
Based on the ball-and-stick model, which shows both the three-dimensional position of the atoms and the bonds tying them together, the 3D chemical structure image of 2,2-Dimethyloctane is created.
In order to provide a clearer picture of the atoms and bonds throughout the 2,2-Dimethyloctane chemical structure model, the radius of the spheres is thus smaller than the rod lengths.

<h3>Molecular Formula - $C_{10} H_{22}$ </h3><h3>Chemical Properties</h3>

Calculated Log P: 6.434
Molecular Weight: 142.2838
Bonds That Rotate: 9
H Acceptors :

H Donors: 0

2,2-Dimethyloctane, a gasoline hydrocarbon byproduct of aerobic biodegradation.

learn more about Dimethyloctane here

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4 0

2 years ago

The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process. In the first step, manganese(I

ale4655 [162]

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:

$Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\$

Equation:

$3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\$

Calculating the amount of $MnCO_3$

$= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\= 13.1 \ kg$

For point b:

$Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\ of\ Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\$

$=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg$

Equation:

$3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\$

Calculating the amount of $MnO_2:$

$= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\= 6516 \ g \\\\=6.52 \ kg\\\\$

7 0

3 years ago