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muminat
3 years ago
8

Salt water is classified as a __________ and a solution. compound mixture​

Chemistry
2 answers:
ELEN [110]3 years ago
7 0

Answer:

compound i had this on usa test prep

Explanation:

REY [17]3 years ago
4 0

Answer: compound

Explanation: because the hydrogen molecules and the oxygen molecules are chemically bonded together unlike in a mixture

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What is the pressure in a gas container that is connected to an open-end U-tube manometer if the pressure of the atmosphere is 7
mojhsa [17]

Answer:

636 mm Hg

Explanation:

The pressure in the gas container is equal to the atmospheric pressure minus the height of mercury:

Atmospheric pressure = 722 torr = 722 mm Hg

Height = 8.60 cm = 86 mm Hg

Pressure = 722 - 86 = 636 mm Hg

So none of the given options is correct, the correct answer is 636 mm Hg.

5 0
3 years ago
How much work (in JJ) is required to expand the volume of a pump from 0.0 LL to 2.5 LL against an external pressure of 1.1 atmat
stira [4]

Answer:

- 278.85 J  

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J  

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm  = - 278.85 J  

8 0
3 years ago
What makes electrons jumo to other orbits around the nucleus then fall again?
Tamiku [17]

Answer:

The higher the excitation state, the more energy the electron contains. When an electron absorbs energy, it jumps to a higher orbital. ... An electron in an excited state can release energy and 'fall' to a lower state.

7 0
3 years ago
Read 2 more answers
In a blast furnace, elemental iron is produced from a mixture of coke (c), iron ore (fe3o4), and other reactants. an important r
jok3333 [9.3K]

Reaction sequence:

2c(s) + o2(g) -> 2co(g)

fe3o4(s) + 4co(g) -> 3fe(l) + 4co2(g)

According to first equation, 2 moles of carbon produce 2 moles of carbon monoxide. So 1 mole of carbon will produce 1 mol of carbon monoxide (the same number).

According to the second equation, 4 moles of carbon monoxide produce 3 moles of iron. We should make the cross multiplication with those numbers:

4 moles CO/3 moles iron = 1 mol CO/x

x = 1 mol CO*3 moles iron/4 moles CO = 0.75 moles of iron

5 0
3 years ago
Consider 2.4 moles of a gas contained in a 4.0 L bulb at a constant temperature of 32°C. This bulb is connected to an evacuated
Luden [163]

Complete Question

The complete question is shown on the first uploaded image

Answer

a

As the valve is opened , the gas will flow into the empty container until the both containers have the same pressure

b

\Delta H = 0\ , \Delta E = 0 , q= 0 , w= 0

c

The driving force for this process is the increase in entropy this is because the movement of the internal energy of the gas into a larger volume, what this does is that it increases the amount of disorder(entropy).

Explanation

In order to obtain the parameter in the part B of the question we are first obtain the initial pressure, using the ideal gas equation  

                      P = \frac{nRT}{V}

                     P = \frac{(2.4mol)(0.0821\frac{1 atm}{K \cdot \ mol} )}{4.0L}

                         P =15 \ atm

The next thing is to obtain the new pressure of the gas , using boyle's law

              P_1V_1 = P_2V_2

                  P_2 = \frac{P_1 V_1}{V_2}

                  P_2 = \frac{(15 \ atm)(4.0L)}{24.0 L}

                  P_2 = 2.5 \ atm    

Since the this process is isothermal , the change in heat is equal to zero

                      i.e  q = 0 J

  The workdone to move  the gas to the other container is zero because the  the pressure at this second container is zero due to the fact that it is a vacuum

    i.e  w = -P_{external} \Delta V

              =-(0 \ atm) (24.0 - 4.0L)

              = 0L \cdot atm

  Since the change in heat is zero and the workdone is zero then the change in internal energy is equal to 0

     This is because the change in internal energy is equal to a summation of change in heat and the workdone

                i.e \Delta E = q + w

                            = 0J

Generally the change in enthalpy is mathematically represented as

                \Delta H = n C_p \Delta T

Since the temperature is zero this means that the change in temperature is zero , substituting this value for change in temperature into the equation for  change in enthalpy

           \Delta H = n C_p (0)

                   = 0J

 

7 0
4 years ago
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