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3 years ago

1. Similarities between alchemy and chemistry include

Chemistry

2 answers:

ValentinkaMS [17]3 years ago

4 0

Answer:

B or C

Explanation:

Alchemy rely a lot on the spiritual connections to the four elements and they are fire, water, earth and air while chemistry is a lot more logical, factual and scientific based. Also, chemistry is considered as science, while alchemy is not.

Alchemy was based more on experimentation and had little basis in science. Chemistry utilizes both experimentation and scientific practices. Modern chemistry basically relies on scientific theories and experimental results, but the alchemy was a blend of myths, religion, magic, astrology, philosophy, and spirituality.

emmasim [6.3K]3 years ago

3 0

Answer:

C Like chemistry, alchemy sought to understand and manipulate matter

Explanation:

Found it in the book

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Which of these terms refers to matter that could be heterogeneous?

Dafna11 [192]

Answer:

B) mixture

Explanation:

Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly of three phases or states of matter are gas, liquid, and solid.

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3 years ago

Lithium has two stable isotopes with masses of 6.01512 amu and 7.01600 amu. The average molar mass of Li is 6.941 amu. What is t

Dvinal [7]

Answer : The percent abundance of Li isotope-1 and Li isotope-2 is, 6.94 % and 93.1 % respectively.

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of Li isotope-1 be 'x' and the fractional abundance of Li isotope-2 will be '100-x'

For Li isotope-1 :

Mass of Li isotope-1 = 6.01512 amu

Fractional abundance of Li isotope-1 = x

For Li isotope-2 :

Mass of Li isotope-2 = 7.01600 amu

Fractional abundance of Li isotope-2 = 100-x

Average atomic mass of Li = 6.941 amu

Putting values in equation 1, we get:

$6.941=[(6.01512\times x)+(7.01600\times (100-x))]$

By solving the term 'x', we get:

$x=694.048$

Percent abundance of Li isotope-1 = $\frac{694.048}{100}=6.94\%$

Percent abundance of Li isotope-2 = 100 - x = 100-6.94 = 93.1 %

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3 years ago

How much of a 400g sample remains after 4 years if a radioactive isotope has a half-life of 2 years?

timama [110]

Answer:

100 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 400 g

Time (t) = 4 years

Half-life (t½) = 2 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Time (t) = 4 years

Half-life (t½) = 2 years

Number of half-lives (n) =?

n = t / t½

n = 4 / 2

n = 2

Thus, 2 half-lives has elapsed.

Finally, we shall determine the amount remaining of the radioactive isotope. This can be obtained as follow:

Original amount (N₀) = 400 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 400

N = 1/4 × 400

N = 0.25 × 400

N = 100 g

Thus, the amount of the radioactive isotope remaing is the 100 g.

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