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BARSIC [14]
3 years ago
13

How does an atom with too many neutrons relative to protons undergo radioactive decay?

Chemistry
2 answers:
jenyasd209 [6]3 years ago
7 0

Answer:

The correct answer is:'<em>by emitting a beta particle'.</em>

Explanation:

An atom with too many neutron relativity in comparison to number of proton will under radioactive decay by the means of beta-decay.

Beta-decay is a radioactive decay process in which a neutron gets converted to into proton and electron as a beta-particle with (-1)charge.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

So , by emitting a beta-particle an atom with more number of neutrons than protons will under radioactive decay.

Naya [18.7K]3 years ago
6 0

by drinking acid and drowning the negative ones and laughing while it slowly kills off half of itself. sorry I know you need this for homework or a test but reading this might make you smile.

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In this question it is quite hard to explain the use of significant figures. Those are used to imply a certain inaccuracy. Not enough information is given by the question, as of how accurate the measurement is. It is a mere exercise of converting one property into another. Here you should not worry about it.
5 0
2 years ago
A beaker contains a mixture of sand and small pebbles. what kind of mixture is this?
melomori [17]
Answer is: a beaker contains <span>heterogeneous mixture.

</span>

A heterogeneous mixture<span> have compounds that remain separate in the sample.</span>

Heterogeneous mixture is not uniform in composition (in this mixture different sand and small pebbles), but proportions of its components (in this mixture particles of different colors and size) vary throughout the sample.

3 0
2 years ago
A student rides a bicycle 240 meters in 4 minutes to get to school what is the student's speed?
pantera1 [17]

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The student's speed is 60 mph.

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6 0
3 years ago
A chemist is given a 3.00M solution of KBr and needs to measure out 0.733 moles of this solution. How many mL of the 3.00M KBr s
Charra [1.4K]

In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.

<h3>What is molarity?</h3>

Molarity (M) is a unit of concentration of solutions, and it is defined as the moles of a solute per liters of a solution.

  • Step 1: Calculate the liters of solution required.

A chemist has a 3.00 M KBr solution and wants to measure 0.733 moles of KBr. The required volume is:

0.733 mol × (1 L/3.00 mol) = 0.244 L

  • Step 2: Convert 0.244 L to mL.

We will use the conversion factor 1 L = 1000 mL.

0.244 L × (1000 mL/1 L) = 244 mL

In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.

Learn more about molarity here: brainly.com/question/9118107

7 0
2 years ago
What will be the final temperature of the solution in a coffee cup calorimeter if a 50.00 mL sample of 0.250 M HCl(aq) is added
padilas [110]

Answer:

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

Explanation:

HCl+NaOH\rightarrow H_2O+NaCl

\Delta H = enthalpy change = -57.2 kJ/mol of NaOH

Moles of sodium hydroxide = n

Molarity of the NaOH = 0.250 M

Volume of NaOH solution = V = 50.00 mL = 0.050 L

n=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Moles of HCl = n'

Molarity of the HCl= 0.250 M

Volume of HCl solution = V' = 50.00 mL = 0.050 L

n'=Molarity\times V=0.250 M\times 0.050 L= 0.0125 mol

Since 1 mole of Hcl reacts with 1 mole of NaoH. Then 0.0125 mole of HCl will react with 0.0125 mole of NaOH.

The enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

q=\Delta H\times n=-57.2 kJ/mol \times 0.0125 mol= -0.715 kJ=-715 J

q = heat released on reaction= -715 J

now, we calculate the heat gained by the solution.:

Q= -q = -(-715 J) = 715 J

m = mass of the solution = ?

Volume of the solution formed by mixing, v = 50.00 ml + 50.00 mL = 100.00 mL

Density of the solution = density of water = d = 1 g/mL

mass=density\times volume=d\times v=1 g/ml \times 100.00 ml=100 g

m = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{f} = final temperature = ?

T_{i} = initial temperature = 19.50^oC

Q=mc\times (T_{f}-T_{i})

Now put all the given values in the above formula, we get:

715 J=100 g\times 4.18J/^oC\times (T_f-19.50)^oC

T_f=21.21 ^oC

21.21°C will be the final temperature of the solution in a coffee cup calorimeter.

5 0
3 years ago
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