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lubasha [3.4K]
3 years ago
10

A student decreases the temperature of 556 cm^3 balloon from 278 K to 231 K. Assuming constant pressure, what should the new vol

ume of the balloon be?
Chemistry
1 answer:
julia-pushkina [17]3 years ago
6 0
In this problem, Charles' law is applicable since constant pressure with varying volume and temperature are given. Charles' law derived from ideal gas law is expressed as \frac{ V_{1} }{ T_{1} }=  \frac{ V_{2} }{ T_{2} }. Subsituting V1=556 cm3, T1=278 K and T2=231 K, V2 or the new volume is 462 cm3. 
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Questions:<br> 1. Why are atomic masses on the periodic table decimal numbers?
fomenos

Answer:

The atomic mass on the periodic table is a decimal number because it is an average of the different isotopes of an element.

P.S.

An isotope is each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

4 0
3 years ago
A 200.0mL closed flask contains 2.000mol of carbon monoxide gas and 2.000mol of oxygen gas at the temperature of 300.0K. How man
max2010maxim [7]

Answer:

There will react 0.400 moles of oxygen.

Explanation:

<u>Step 1:</u> Data given

Volume of the closed flask = 200.00 mL = 0.2 L

Number of moles of CO = 2.000 mol

Number of moles of O2 = 2.000 mol

Temperature = 300.0 K

Pressure decreases with 10%

<u>Step 2</u>: The balanced equation

2CO(g)+O2(g)⟶2CO2(g)

<u>Step 3</u>: Calculate the initial pressure of the flask before the reaction

P = nRT/V

⇒ with n = the number of moles (2.000 moles CO + 2.000 moles O2 = 4.000 moles)

⇒ R is gas constant (0.08206 atm*L/mol*K)

⇒T = the  temperature = 300.0K

⇒ V = the volume = 200.0 mL = 0.2 L

P = (4 * 0.08206*300)/0.2

P = 492.36 atm

<u>Step 4:</u> When the pressure is 10 % decreased:

The final pressure = 492.36 - 49.236 = 443.124 atm

<u>Step 5:</u> Calculate the number of moles

n = PV/RT

⇒ with n = the number of moles

⇒ with P = the pressure = 443.124 atm

⇒ V = the volume = 200.0 mL = 0.2 L

⇒ R is gas constant (0.08206 atm*L/mol*K)

⇒T = the  temperature = 300.0K

n =(443.124*0.2)/(0.08206*300)

n = 3.6 moles = total number of moles

<u>Step 6:</u> Calculate number of moles

For the reaction :2CO(g) + O₂(g) ⟶ 2CO₂(g)

For each mole of O2 we have 2 moles of CO, to produce 2 moles of CO2

Moles CO = (2 -2X) moles

Moles O2 = (2-X) moles

Moles CO2 = 2X

The total number of moles (4 -X)= 3.6 moles

Where X are moles that react

X = 0.400 moles

There will react 0.400 moles of oxygen.

6 0
3 years ago
If the H+ in a solution is 1x10^-1 mol/L what is the OH-
damaskus [11]
PH scale is used to determine how acidic or basic a solution is.
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8 0
3 years ago
How many chiral centres are there in warfarin molecule?
kolbaska11 [484]
I'm actually not sure... but maybe this will help!
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6 0
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