1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lubasha [3.4K]
2 years ago
10

A student decreases the temperature of 556 cm^3 balloon from 278 K to 231 K. Assuming constant pressure, what should the new vol

ume of the balloon be?
Chemistry
1 answer:
julia-pushkina [17]2 years ago
6 0
In this problem, Charles' law is applicable since constant pressure with varying volume and temperature are given. Charles' law derived from ideal gas law is expressed as \frac{ V_{1} }{ T_{1} }=  \frac{ V_{2} }{ T_{2} }. Subsituting V1=556 cm3, T1=278 K and T2=231 K, V2 or the new volume is 462 cm3. 
You might be interested in
A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o
atroni [7]

The reaction for burning of charcoal or complete combustion is as follows:

C(s)+O_{2}(g)\rightarrow CO_{2}(g)

From the above balanced reaction, 1 mole of carbon releases 1 mole of CO_{2} gas.

Converting mass of charcoal into moles as follows:

n=\frac{m}{M}

Molar mass of pure carbon is 12 g/mol thus,

n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol

The same moles of CO_{2} is released. Converting these moles into mass as follows:

m=n×M

Molar mass of CO_{2} is 44 g/mol thus,

m=125mol\times 44 g/mol=5.5\times 10^{3}g

Converting mass into kg,

1g=10^{-3}kg

Thus, total mass of gas released is 5.5 kg.

7 0
3 years ago
Twenty students were surveyed to find out how many hours of TV they watch during a school week. The results are shown to the rig
natulia [17]

Answer: 4.5

Explanation:

Just did it

8 0
2 years ago
Read 2 more answers
Give the name and symbol of the prefixes used with SI units to indicate multiplication by the following exact quantites.
Bingel [31]

Answer:

A. Kilo , K, multiplication by 1000

B. Centi, c

C. Deci, d

D. Mili, m

E. Mega, M

F. Micro, u

7 0
3 years ago
How many molecules are in 1kg of water
Mila [183]

Answer:

334.2× 10²³ molecules

Explanation:

Given data:

Mass of water = 1 Kg ( 1000 g )

Number of molecules = ?

Solution:

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 1000 g/ 18 g/mol

Number of moles = 55.5 mol

1 mole contain 6.022× 10²³ molecules

55.5 mol×6.022× 10²³ molecules

334.2× 10²³ molecules

8 0
3 years ago
How can you determine the number of atoms in a mole of a molecular compound
Brilliant_brown [7]
Well if you go to Quiz-let it gives the answer the mass of a mole of compound is determined by adding the atomic masses of the atoms making up the molecules
7 0
2 years ago
Other questions:
  • Order the levels of organization from the smallest (1) to the largest (4).
    6·1 answer
  • Hydrogen gas can be made by reacting methane (CH4) with high temperature steam: CH4(g) + H2O(g) ---> CO(g) + 3H2(g)
    10·2 answers
  • You wish to make a 0.435 M perchloric acid solution from a stock solution of 3.00 M perchloric acid. How much concentrated acid
    12·1 answer
  • What compotent of air is least nessasery for life on earth
    12·1 answer
  • What causes eclipses? Check all that apply.
    7·2 answers
  • "All plants perform photosynthesis. The cactus on my windowsill is a plant, therefore it must be performing photosynthesis." Thi
    10·1 answer
  • For the following reaction, 35.4 grams of zinc oxide are allowed to react with 6.96 grams of water . zinc oxide(s) + water(l) --
    9·1 answer
  • What is the temperature of the flame in degrees Celsius?
    7·1 answer
  • If you start with 4 moles of iron and 3 moles of oxygen to produce iron oxide, what is the limiting reagent? (You will need to b
    8·1 answer
  • 2. Calculate the atomic mass of the following elements i. Silicon ii. Magnesium iii. Potassium.​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!