Question

A student decreases the temperature of 556 cm^3 balloon from 278 K to 231 K. Assuming constant pressure, what should the new volume of the balloon be?

Answer 1

In this problem, Charles' law is applicable since constant pressure with varying volume and temperature are given. Charles' law derived from ideal gas law is expressed as $\frac{ V_{1} }{ T_{1} }= \frac{ V_{2} }{ T_{2} }$. Subsituting V1=556 cm3, T1=278 K and T2=231 K, V2 or the new volume is 462 cm3.